Answer:
W = 0.49 N
τ = 0.4851 Nm
Force
Explanation:
The weight force can be found as:
W = mg
W = (0.05 kg)(9.8 m/s²)
<u>W = 0.49 N</u>
The torque about the pivot can be found as:
τ = W*d
where,
τ = torque
d = distance between weight and pivot = 99 cm = 0.99 m
Therefore,
τ = (0.49 N)(0.99 m)
<u>τ = 0.4851 Nm</u>
The pivot exerts a <u>FORCE </u>on the meter stick because the pivot applies force normally over the stick and has a zero distance from stick.
Answer:
-0.01052 m/s
Explanation:
M = mass of ship = 
m = mass of shell = 1100 kg
v = velocity of shell = 550 m/s
u = recoil velocity of ship
As linear momentum is conserved

The recoil velocity of the ship taking the firing direction to be the positive direction is -0.01052 m/s
Answer:
This is your answer
Explanation:
Actually I took this from go ogle