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Svetllana [295]
3 years ago
9

What's faster a slow car or a fast feather?​

Physics
2 answers:
krok68 [10]3 years ago
5 0

Answer:

A fast feather

Explanation:

The faster any item is, the more momentum it has

zhuklara [117]3 years ago
5 0

Answer:

Explanation:idk

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sammy [17]
To heat up leftovers, to make dinner faster or melt chocolate
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You are handed a 5.00x10^-3kg coin and told that it is gold.
aksik [14]

Answer:

thats cool, gold is pretty

Explanation:

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7 0
2 years ago
How do you use vectors daily without realizing it was a vector?<br><br> I need help ASAP !!!
jonny [76]

Explanation:

Vectors are quantities that has both magnitude and direction. A vector is described in terms of quantity and the direction it is headed.

There are different forms of vectors that are used in our daily life.

  • When we describe the motion of a car and the direction it is heading, we are simply talking about its velocity which is a vector.
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6 0
3 years ago
a 1.5 kg ball is thrown vertically upward with an initial speed of 15 m/s. if the initial potential energy is taken as zero, fin
trapecia [35]

Answer:

a) E_{p} = 0

E_{k} = 168.7 J

E_{m} = 168.7 J

b) E_{p} = 73.6 J

E_{k} = 95.8 J

E_{m} = 169.4 J

c) E_{p} = 169.2 J

E_{k} = 0

E_{m} = 169.2 J

Explanation:

We have:

m: is the ball's mass = 1.5 kg

v₀: is the initial speed = 15 m/s

g: is the gravity acceleration = 9.81 m/s²

a) In the initial position we have:

h: is the height = 0

The potential energy is given by:

E_{p} = mgh = 0

The kinetic energy is:

E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(15)^{2} = 168.7 J

And the mechanical energies:

E_{m} = E_{p} + E_{k} = 0 + 168.7 J = 168.7 J

b) At 5 m above the initial position we have:

h = 5 m

The potential energy is:

E_{p} = mgh = 1.5*9.81*5 = 73.6 J

Now, to find the kinetic energy we need to calculate the speed at 5 m:

v_{f}^{2} = v_{0}^{2} - 2gh = (15)^{2} - 2*9.81*5 = 126.9

v_{f} = \sqrt{126.9} = 11.3 m/s

E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(11.3)^{2} = 95.8 J

And the mechanical energies:

E_{m} = E_{p} + E_{k} = 73.6 + 95.8 J = 169.4 J

c) At its maximum height:

v_{f}: is the final speed = 0

h = \frac{v_{0}^{2}}{2g} = \frac{(15)^{2}}{2*9.81} = 11.5 m

Now, the potential, kinetic and mechanical energies are:

E_{p} = mgh = 1.5*9.81*11.5 = 169.2 J

E_{k} = \frac{1}{2}mv^{2} = 0

E_{m} = 169.2 J + 0 = 169.2 J

I hope it helps you!    

7 0
2 years ago
A woman throws a baseball straight up into the air. what is the baseball's acceleration at its highest point?
AleksandrR [38]
After the ball leaves the woman's hand, the only relevant force acting on the ball is the gravity, which produces an acceleration of a=g=9.81 m/s^2 on the baseball, directed downward. 
Gravity acts on the ball for the whole duration of the motion, so the acceleration of the ball is g=9.81 m/s^2 at every point of the motion, and therefore also when the baseball is at its highest point.
5 0
3 years ago
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