You do the butterfly method multiply across and add or subtract. multiply the denominators to get the denominators
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The standard form for the equation of a circle is :
<span><span> (x−h)^2</span>+<span>(y−k)^2</span>=r2</span><span> ----------- EQ(1)
</span> where handk are the x and y coordinates of the center of the circle and r<span> is the radius.
</span> The center of the circle is the midpoint of the diameter.
So the midpoint of the diameter with endpoints at (2,-5)and(8,-9) is :
((2+(8))/2,(-5+(-9))/2)=(5,-7)
So the point (5,-7) is the center of the circle.
Now, use the distance formula to find the radius of the circle:
r^2=(2−(5))^2+(-5−(-7))^2=9+4=13
⇒r=√13
Subtituting h=5, k=-7 and r=√13 into EQ(1) gives :
(x-5)^2+(y+7)^2=13
All functions are relations, but not all relations are functions. A function is a relation that for each input, there is only one output.
EXPLANATION;
Functions are relations that have only one output for any unique input. To tell whether a graphed relation defines a function, you can use the vertical line test.
Answer:
Step-by-step explanation:
<u>The difference of −2d and −3d is equal to the difference of 1/6 and 1/3</u>
- -2d - (-3d) = 1/6 - 1/3
- -2d + 3d = 1/6 - 2/6
- d = -1/6
