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3 years ago

Is the relation a function? explain

Mathematics

2 answers:

Llana [10]3 years ago

8 0

All functions are relations, but not all relations are functions. A function is a relation that for each input, there is only one output.

EXPLANATION;

Functions are relations that have only one output for any unique input. To tell whether a graphed relation defines a function, you can use the vertical line test.

Elden [556K]3 years ago

3 0

All functions are relations, but not all relations are functions. A function is a relation that for each input, there is only one output.

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Copy the following number line, and mark each number on your number line. I've never been good with number lines!

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4 years ago

Read 2 more answers

M mrs. Gallegos Burns 236 calories riding her bike each hour she wants to burn more than 590 calories riding her bike at the sam

NeX [460]

Answer: x > 2.5

Step-by-step explanation:

Since Mrs Gallegos burns 236 calories riding her bike each hour and she wants to burn more than 590 calories riding her bike at the same rate, the inequality that will represent the number of hours that she will use will be:

x > 590/236

x > 2.5

She must ride the bike for more than 2 1/2 hours to burn more than 590 calories.

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3 years ago

Which of the following terms appear in the expansion of (x+y)^10? The letter "a" in each term represents a real constant.

Vinvika [58]

ANSWER

$ax^4y^6$

$ax^3y^7$

$ax^6y^4$

EXPLANATION.

The given binomial is

$( {x + y)}^{10}$

One property about all the terms in this binomial expansion is that:

The degree of each term is 10.

$ax^4y^6$

degree=4+6=10

$ax^3y^7$

degree=3+7=10

$ax^6y^4$

degree=6+4=10

$ax^5$

degree=5+0=5

All the terms with degree 10 are the correct options

7 0

3 years ago

Is 30/100 equivalent to 3/1000?

andre [41]

No it is not equivalent

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4 years ago

Which of the following relation is correct

o-na [289]

Answer:

Both the equation and its inverse are functions.

Step-by-step explanation:

In order to solve this problem lets first find the inverse of this function. This is done below:

$y = x^2 + 8\\$

We first swap x and y.

$x = y^2 + 8$

We now isolate y.

$y^2 = x - 8\\y = \sqrt{x - 8}\\f^{-1}(x) = \sqrt{x - 8}$

Functions are relations between two groups of numbers, in such a way that one number on the input group must generate a singular answer from the output group. This holds true for both f(x) and its inverse, therefore both are functions.

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4 years ago

Is the relation a function? explain ​

Is the relation a function? explain