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3 years ago

Please help me i have no idea :(

Mathematics

1 answer:

marshall27 [118]3 years ago

3 0

Answer:

The last answer

Step-by-step explanation:

$z =k \frac{x}{ {y}^{2} }$

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Choose the equation that could be used to solve this problem.

Naddik [55]

Answer:

425

Step-by-step explanation:

4 0

2 years ago

Write two expressions where the solution is 41.

ladessa [460]

One expression could be.... Nine times 4 plus five equals forty one. ALSO... Eight times eight equals sixty four then subtract twenty four equals forty one

8 0

3 years ago

At 6:00 A.M. the temperature was 33°F. By noon the temperature had increased by 10°F and by 3:00 P.M. it had increased another 1

chubhunter [2.5K]

So let's see here...

6:00 A.M. temperature is 33°F.

12:00 P.M temperature increased by 10°F making it 43°F.

3:00 P.M. temperature increased by another 12°F making it 55°F.

At 10:00 P.M it would decrease by 15°F making it 40°F.

The temperature would need to fall (or decrease) by 7°F to reach the original temperature of 33°F

Hope this helped!

3 0

2 years ago

Find the discriminant of the following quadratic equation then state the number of rational, irrational, and imaginary solutions

lianna [129]

Answer:

-6x² - 6 = -7x - 9
-6x² + 7x - 6 + 9 = 0
-6x² + 7x + 3 = 0
6x² - 7x - 3 = 0

<u>Discriminant:</u>

D = (-7)² - 4*6*(-3) = 49 + 72 = 121

<u>Since D > 0, there are 2 real solutions:</u>

x = (- (-7) ±√121 )/12
x = (7 ± 11)/12
x = 1.5, x = -1/3

8 0

3 years ago

Read 2 more answers

What is the distance between nicholas's school and the post office?

aleksklad [387]

Part A:

Given that Nicholas's school is located at point (3, 2) and that the post office is located at point (-2, -2), then the distance between Nicholas's school and the post office is given by:

$d= \sqrt{(-2-3)^2+(-2-2)^2} \\ \\ = \sqrt{(-5)^2+(-4)^2} = \sqrt{25+16} \\ \\ \sqrt{41} =\bold{6.4} \ units$

Part B:

If Nicholas is located at point (– 3 , 2), the distance to get to the grocery store located at point (1,-1) is given by:

$d= \sqrt{(1-(-3))^2+(-1-2)^2} \\ \\ = \sqrt{(1+3)^2+(-3)^2} = \sqrt{(4)^2+9} \\ \\ = \sqrt{16+9} = \sqrt{25} =\bold{5}$

4 0

3 years ago