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gogolik [260]
3 years ago
11

Help me plz. You have to evaluate the expression.

Mathematics
1 answer:
Ray Of Light [21]3 years ago
3 0

Answer:

2+4 + 0+ 1 = $7

Step-by-step explanation:

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Select all the answers !
ki77a [65]

Answer:

1,3 and 4

it is what it be

3 0
2 years ago
I need help I have been stuck on it FOREVER!!!
ira [324]

Answer:

22.

Step 1: Find area of inner square = 4 ft × 12 ft = 48ft2

Step 2: Find area of outer shape =

25 ft +11 ft = 36 cm2

Step 3: Area of shaded region = area of outer shape – area of inner square

= 36 ft2 – 48 ft2

= 12 ft2

8 0
2 years ago
Read 2 more answers
The ratio of the sides of 2 cubes is 2 to 7. If the volume of the smaller cube is 32 u3, then the volume of the larger cube is _
satela [25.4K]
\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\

\bf \cfrac{small}{large}\qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\implies \cfrac{2}{7}=\cfrac{\sqrt[3]{32}}{\sqrt[3]{v}}\implies \cfrac{2}{7}=\sqrt[3]{\cfrac{32}{v}}\implies \left( \cfrac{2}{7} \right)^3=\cfrac{32}{v}
\\\\\\
\cfrac{2^3}{7^3}=\cfrac{32}{v}\implies v=\cfrac{7^3\cdot 32}{2^3}
5 0
3 years ago
Prove, cotx -tanx= 2 cot2x
ra1l [238]

Step-by-step explanation:

<em>cotx-</em><em> </em><em>tanx</em><em>=</em><em> </em><em>2cot2x</em>

<em>L.H.S</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>cosx</em><em>/</em><em>sinx-</em><em> </em><em>sinx</em><em>/</em><em>cosx</em><em> </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>cos</em><em>²</em><em>x-</em><em> </em><em>sin</em><em>²</em><em>x</em><em>)</em><em>/</em><em> </em><em>sinxcosx</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>[</em><em> </em><em>cos</em><em>²</em><em>x-</em><em>(</em><em>1</em><em>-cos</em><em>²</em><em>x</em><em>)</em><em>]</em><em>/</em><em>sinxcosx</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em> </em><em>2cos</em><em>²</em><em>x-1</em><em>)</em><em>/</em><em>sinxcosx</em>

<em> </em><em> </em><em> </em><em>2cosx</em><em>/</em><em> </em><em>2sinxcosx</em>

<em> </em><em> </em><em> </em><em>2cot2x</em>

4 0
2 years ago
Hey can anyone help me find the missing side lengths please and thank you
alex41 [277]

Answer:

choice a

Step-by-step explanation:

angle 45 means, its a isosceles triangle.

so y = √3

x^2 = 3+3= 6

x = √6

3 0
2 years ago
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