I assume (x-4)3 means (x-4)³. What we wish is to set the derivative equal to zero.
Expanding the T(x) polynomial makes it easier for me to take the derivative.
So (x-4)³ = x³ - 12x² + 48x - 64 + 6
T'(x) = 3x² - 24x + 48
We can factor out a 3 and set this to zero:
x² - 8x + 16 = 0
(x -4)² = 0
x = 4 should therefore represent the turning point.
I am mildly chagrined, I almost used the f'(x) = nx^(n-1) function at first, which appears would have been correct.
Answer:
Tonya proof is correct
and Pearl proof is wrong
Step-by-step explanation:
AKL and GKB are obviously congruent. But the reasons given are different, One of the justification is Vertical Angles Theorem, and the other is Adjacent Angles.
But the correct justification is the Vertical Angles Theorem, because the angles are Vertically away from each other, or the angles are at opposite sides of each other. Which is when Vertical Angles Theorem is applied.
Making Tonya correct since that was the answer he given.
The definition of Adjacent Angles is incorrect, this Theorem is used when the angles are Adjacent to each other. When the angles are on the same line as the other angle, is when the definition of Adjacent Angles is applied. Not in this situation
160 = (10 + x) + x + 4x
160 = 6x + 10
150 = 6x
150/6 = x
x = 25
second number = x = 25
third number = 4x = 100
first number = x + 10 = 35
Answer:
s = -3
Step-by-step explanation:
1 = 4s + 13
rewrite
4s + 13 = 1
4s = 1 - 13
4s = -12
s = -3
Answer:
12 literaly how old are u bro
Step-by-step explanation:
