5/1 is the answer................................
Answer:
Amount of Winter sealer for 2 coats[in square feet] = 576 square feet
Step-by-step explanation:
Given:
Length of drive way at garage door = 12 feet
Length of drive way at street = 20 feet
Length of total driveway = 18 feet
Find:
Amount of Winter sealer for 2 coats[in square feet]
Computation:
Amount of Winter sealer for 2 coats[in square feet] = 2[Area of trapezoid]
Amount of Winter sealer for 2 coats[in square feet] = 2[(1/2)(Sum of parallel side)(Height)]
Amount of Winter sealer for 2 coats[in square feet] = 2[(1/2)(12 + 20)(18)]
Amount of Winter sealer for 2 coats[in square feet] = 2[(1/2)(32)(18)]
Amount of Winter sealer for 2 coats[in square feet] = 32 x 18
Amount of Winter sealer for 2 coats[in square feet] = 576 square feet
L = A/W
Length equals area divided by width
A
This is like a base form of a prime polynomial
X^2+x+1
Answer:
B= 133° C= 47°
Step-by-step explanation:
As shows on the right it's 133°
A= 133°
c+a =180° -a
= 180° -133°
=47°
a and c complement each other and
b= a = 133°
a and b are vertical angles
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