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konstantin123 [22]
3 years ago
10

What is the degree of the following polynomial 2x^3

Mathematics
1 answer:
ddd [48]3 years ago
7 0

Answer:

3

Step-by-step explanation:

Whatever the highest exponent is determines the degree.

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Write the first 4 terms in the sequence defined by the explicit rule f(n)=n^2 - 5 *n^2 means n squared
Deffense [45]
The question did not spesify the stating value for n.

Assuming, n = 0 is the starting value.

1st term is when n = 0:
f(0) = (0)^2 - 5 = 0 - 5 = -5

2nd term: f(1) = (1)^2 - 5 = 1 - 5 = -4

3rd term: f(2) = (2)^2 - 5 = 4 - 5 = -1

4th term: f(3) = (3)^2 - 5 = 9 - 5 = 4

Therefore, the first 4 terms are: -5, -4, -1, 4.
6 0
3 years ago
Write ✓-3 in simplest radical form.
olga nikolaevna [1]

Step-by-step explanation:

In simplest radical form

= √-3

= -3^(1/2)

or

= √-3

= √3i

i is imaginary number, you can write it if you find a negative number in a square root

7 0
3 years ago
Help is much needed!!!
icang [17]
Y - y1 = m (x + x1)

Solve for m by subtracting the y's and dividing them by the difference of the 2 x's.

-32 - 1 = -33
-8 - 3 = -11

Divide the two to get 3.

Use the first point (as instructed) and plug it into the equation.

y - (-32) = 3 (x - (-8))

y + [32] = [3] (x + [5])

The brackets are the fill in the blanks.
5 0
3 years ago
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