Answer:
Step-by-step explanation:
7/18=7/18
it cant be divided agian
1/3=1/3
it cant be divded agian
1/5=1/5
it cant be divded agian
1/10=1/10
it cant be divded agian
3 1/2=3/2
2 5/9 =10/9
i am not sure if this is what you wanted ...
Answer:
Robbie Glider
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Step-by-step explanation:
Given
<u>Melissa Glider</u>
<u>Robbie Glider</u>
See attachment for function
Required
Which reaches the greater maximum within the first 6 seconds
<u>Melissa Glider</u>
First, we calculate the maximum of Melissa's glider
Differentiate:
Equate to 0 to find the maximum
Divide through by 0.4
Solve for s using quadratic formula:
Where
So:
Split:
This implies that Melissa's glider reaches the maximum at 5.4 seconds or 1.9 seconds.
<em>Both time are less than 6 seconds</em>
Substitute 5.4 and 1.9 for s in to get the maximum
The maximum is 10.02ft for Melissa's glider
<u>Robbie Glider</u>
From the attached graph, within an interval less than 6 seconds, the maximum altitude is at 3 seconds
<em>Compare both maximum altitudes, 22ft > 10.02ft. This implies that Robbie reached a greater altitude</em>
Answer:
Step-by-step explanation:
Hey this is long division polynomials, my work is a little confusing and I see that you do not need to show step so ill skip it.
If you don't understand I recommand search a video on it
<3
Red
Answer:
3 years
Step-by-step explanation:
In this problem, the initial number of students at time t = 0 is
We know that the number of students increases by 5 % every year. This means that we can write the student's population as
where
t is the time, measured in years
Here we want to find after how many years t the student's population will exceed the maximum capacity of the school, which is
N = 1100
To solve the problem, we just put n = 1100 and we solve for t. We find:
Which means that the student's population reaches the maximum capacity of the school after 2.37 years. Since we want this number to be an integer, this means that the enrollment will exceed the capacity in 3 years.