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oee [108]
3 years ago
10

Which biogeochemical cycle is not reliant upon decomposers?

Mathematics
2 answers:
Ksju [112]3 years ago
8 0

Answer:

1. Carbon Cycle

Step-by-step explanation:

wariber [46]3 years ago
5 0
1. carbon cycle.................
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What is the point-slope form of a line with slope 3 that contains the point (2,1)?
Serjik [45]

Answer:

A) y-1=3(x-2)

Step-by-step explanation:

Point-slope formula.

y-y_1=m(x-x_1)

Given.

Slope (m) = 3

Points (x, y) = (2, 1)

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I need help! Find the measure of all sides. Round to the nearest tenth.
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Answer:

let \: the \: angle \: be \:  \alpha  \\  \tan( \alpha )  =  \frac{p}{b}  \\  \tan(16.8) =   \frac{2.7}{x}  \\ x =  \frac{2.7}{0.30 }  \\ x = 9 \\ now \: by \: using \: pythagoras \: theorem \:  \\ h =  \sqrt{p {}^{2} }  + b {}^{2}  \\ h =  \sqrt{ {2.7}^{2} }  +  {9 }^{2}  \\ h = 9.396

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2 years ago
Line "AB" and line "CD" are perpendicular and intersect at point P. What is the measure of angle APC?​
Step2247 [10]

Answer:

APC is 90 degrees

Step-by-step explanation:

When lines intersect and are perpendicular. that means the angle of intersection is 90 degrees.

APC is 90 degrees

7 0
3 years ago
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What is the circumference of a circle whose diameter is 4.8 cm?
DaniilM [7]

Answer:

15.072

Step-by-step explanation:

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=  4.8π

=  15.079644737231

6 0
3 years ago
Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discha
mr Goodwill [35]

Answer:

Step-by-step explanation:

Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discharging hot water into the river is given by

T(x) = 160-0.05x^2

a. [0, 10]

For x = 0

T(0) = 160 - 0.05 × 0^2

T(0) = 160

For x = 10

T(10) = 160 - 0.05 × 10^2

T(10) = 160 - 5 = 155

The average temperature

= (160 + 155)/2 = 157.5

b. [10, 40]

For x = 10

T(10) = 160 - 0.05 × 10^2

T(10) = 160 - 5 = 155

For x = 40

T(10) = 160 - 0.05 × 40^2

T(10) = 160 - 80 = 80

The average temperature

= (80 + 155)/2 = 117.5

c. [0, 40]

For x = 0

T(0) = 160 - 0.05 × 0^2

T(0) = 160

For x = 40

T(10) = 160 - 0.05 × 40^2

T(10) = 160 - 80 = 80

The average temperature

= (160 + 80)/2 = 120

6 0
3 years ago
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