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3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Mathematics

1 answer:

djyliett [7]3 years ago

4 0

To solve this problem you must apply the proccedure shown below:
To match each equation with its y-intercept x must be zero, so you have:
x=0 and solve for y, as following:

1) cx+by=a (0,a/b)
y=a/b
2) bx+ay=c (0,c/a)
y=c/a
3) ax+by=c (0,c/b)
y=c/b
4) cx+ay=b (0,b/a)
y=b/a

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What is the product of 3/5 x 4/9 written in simplest form?

frosja888 [35]

Mmm... I think it is 5/8... I think.

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3 years ago

Read 2 more answers

What will be the cost price of a television when

astra-53 [7]

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3 years ago

Eli had $10 but he lost some of it. He mom doubled the money he had left. Eli wrote the expression 2(10-k) how much money he has

bezimeni [28]

Answer:

Step-by-step explanation:

According to the first expression:

2(10-k): where,

2:shows the double amount of money which ELI has

10:shows the amount of money which ELI had at the starting.

k:shows the amount of money which is lost.

10-k:shows the amount of money which ELI has after losing some amount.

According to the second expression:

20-2k where,

20:shows the twice of initial amount.

k: is the amount of money which is lost

2k:s hows the twice of amount which is lost

20-2k: shows the amount of money which is left with ELI after his mom gave him some money....

7 0

3 years ago

If function F is defined by f(x) = 3x^2 + 5, what is f(x-4)

shepuryov [24]

Answer:

The function f(x) when x=x-4 is $f(x-4)=3x^2-24x+53$ or $f(x-4)=3x(x-8)+53$

Step-by-step explanation:

Given function f is defined by $f(x)=3x^2+5$

Now to find the function f(x-4):

$f(x)=3x^2+5$

Put x=x-4 in the above function we get

$f(x-4)=3(x-4)^2+5$

$f(x-4)=3(x^2-2(x)(4)+4^2)+5$ (using the formula $(a-b)^2=a^2-2ab+b^2$ )

$f(x-4)=3(x^2-8x+16)+5$

$f(x-4)=3x^2-24x+48+5$ (adding the like terms)

$f(x-4)=3x^2-24x+53$

$f(x-4)=3x(x-8)+53$

Therefore $f(x-4)=3x^2-24x+53$ or $f(x-4)=3x(x-8)+53$

The function f(x) when x=x-4 is $f(x-4)=3x^2-24x+53$ or $f(x-4)=3x(x-8)+53$

4 0

3 years ago

Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2

drek231 [11]

Answer:

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is $x^{3}-2 x^{2}-x+2=0$

Solution:

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is

$F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0$

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

$F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0$

$\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}$

So, the equation is $x^{3}-2 x^{2}-x+2=0$

Let us put x = 0 in f(x) to check whether our answer is correct or not.

$\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2$

Hence, the equation of the polynomial is $x^{3}-2 x^{2}-x+2=0$

3 0

3 years ago