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3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Mathematics

1 answer:

djyliett [7]3 years ago

4 0

To solve this problem you must apply the proccedure shown below:
To m<span>atch each equation with its y-intercept x must be zero, so you have:
x=0 and solve for y, as following:

1) cx+by=a (0,a/b)
y=a/b
2) bx+ay=c (0,c/a)
y=c/a
3) ax+by=c (0,c/b)
y=c/b
4) cx+ay=b (0,b/a)
y=b/a
</span>

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Given right triangle ABC with right angle at C, find sin A if a=8 and b=15

Svetllana [295]

Answer:

if you are lookng for C it is 17

Step-by-step explanation:

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3 years ago

Helppp! Is Figure A’B’C’D’ a reflection of Figure ABCD? Explain. *

Korolek [52]

Yes. It would be a reflection over the line.

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3 years ago

Nathan took his car in for service and repairs. He had a coupon for 10% off. Original Prices • Labor $218.97 • Parts $303.47 • O

Dmitry_Shevchenko [17]

Answer:

C PLEASE GIVE BRAINLIEST

Step-by-step explanation:

218.97 + 303.47 + 77.78 = $600.22

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600.22 - 60.02 = $540.20 (amount he owes)

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3 years ago

Read 2 more answers

-2x+3=9. What does x equal?

Dimas [21]

Answer:

Step-by-step explanation:

$- 2x + 3 = 9 \\ - 2x = 9 - 3 \\ - 2x = 6 \\ \frac{ - 2x}{ - 2} = \frac{6}{ - 2}$

$x = - 3$

3 0

3 years ago

Read 2 more answers

A parabola has a focus of F(2, -0.5) and a directrix of y=-1.5 P(x,y) represents any point on the parabola, while D(x, -1.5) rep

prohojiy [21]

The sketch of the parabola is attached below

We have the focus $(a,b) = (2, -0.5)$
The point $P(x,y)$
The directrix, c at $y=-1.5$

The steps to find the equation of the parabola are as follows

Step 1
Find the distance between the focus and the point P using Pythagoras. We have two coordinates; $(2, -0.5)$ and $(x,y)$ .
We need the vertical and horizontal distances to find the hypotenuse (the diagram is shown in the second diagram).
The distance between the focus and point P is given by
$\sqrt{ (x-a)^{2}+ (y-b)^{2} }$

Step 2
Find the distance between the point P to the directrix $c$ . It is a vertical distance between y and c, expressed as $y-c$

Step 3
The equation of parabola is then given as
$\sqrt{ (x-a)^{2}+ (y-b)^{2} }$ = $y-c$
$(x-a)^{2}+ (y-b)^{2}= (y-c)^{2}$ ⇒ substituting a, b and c
$(x-2)^{2}+ (y--0.5)^{2} = (y--1.5)^{2}$
$(x-2)^{2}+ (y+0.5)^{2}= (y+1.5)^{2}$ ⇒Rearranging and making $y$ the subject gives

$y= \frac{ x^{2} }{2} -2x+1$

7 0

3 years ago