Answer:
1100 field-side tickets and 4500 end-zone tickets.
Step-by-step explanation:
Let x represent number of field side tickets and y represent number of end-zone tickets.
We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:
![x+y=5600...(1)](https://tex.z-dn.net/?f=x%2By%3D5600...%281%29)
We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
Cost of x field side tickets would be
and cost of y end-zone tickets would be
.
The total amount of money received for the tickets was $134000. We can represent this information in an equation as:
![40x+20y=134000...(2)](https://tex.z-dn.net/?f=40x%2B20y%3D134000...%282%29)
Upon substituting equation (1) in equation (2), we will get:
![40x+20(5600-x)=134000](https://tex.z-dn.net/?f=40x%2B20%285600-x%29%3D134000)
![40x+112000-20x=134000](https://tex.z-dn.net/?f=40x%2B112000-20x%3D134000)
![20x+112000=134000](https://tex.z-dn.net/?f=20x%2B112000%3D134000)
![20x+112000-112000=134000-112000](https://tex.z-dn.net/?f=20x%2B112000-112000%3D134000-112000)
![20x=22000](https://tex.z-dn.net/?f=20x%3D22000)
![\frac{20x}{20}=\frac{22000}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B20x%7D%7B20%7D%3D%5Cfrac%7B22000%7D%7B20%7D)
![x=1100](https://tex.z-dn.net/?f=x%3D1100)
Therefore, 1100 field side tickets were sold.
Upon substituting
in equation (1), we will get:
![y=5600-1100](https://tex.z-dn.net/?f=y%3D5600-1100)
![y=4500](https://tex.z-dn.net/?f=y%3D4500)
Therefore, 4500 end-zone tickets were sold.
Answer:
x=5
Step-by-step explanation:
-5x+6(5x-18)=17
-5x+30x-108=17
25x-108=17
25x=17+108
25x=125
x=5
Answer:
2.5 is the best deal
Step-by-step explanation:
hope this helps
Answer:
x = 10, x = 124
Step-by-step explanation:
(5)
Since Δ JKL is isosceles then the base angles are congruent, that is
∠ LJK = ∠ LJG = 80° , thus
∠ JLK = 180 - (80 + 80) = 180 - 160 = 20
x = 20 ÷ 2 = 10
(6)
Since Δ PQR is equilateral, then each of its angles = 60°
∠QRS = 60° - 32° = 28°
Since Δ SQR is isosceles then base angles are congruent, then
∠ SQR = ∠ QRS = 28 , thus
x = 180 - (28 + 28) = 180 - 56 = 124