Answer:
There is no need to make an algorithm for this simple problem. Just add the two numbers by storing in two different variables as follows:
Let a,b be two numbers.
c=a+b;
print(c);
But, if you want to find the sum of more numbers, you can use any loop like for, while or do-while as follows:
Let a be the variable where the input numbers are stored.
while(f==1)
{
printf(“Enter number”);
scanf(“Take number into the variable a”);
sum=sum+a;
printf(“Do you want to enter more numbers? 1 for yes, 0 for no”);
scanf(“Take the input into the variable f”);
}
print(Sum)
Explanation:
hi there answer is given mar me as brainliest
Answer:
The JavaScript statement is
var str1 = "Information Technology";
var result = str1.toUpperCase();
Explanation:
JavaScript is used to validate the client side it means it provide the client side validation.
Following are the function of JavaScript that converted the string into uppercase.
function val()
{
var str1 = "Information Technology ";
var result = str1.toUpperCase();
}
The toUpperCase() function convert the string into uppercase in JavaScript
OUTPUT
INFORMATION TECHNOLOGY
Answer:
See Explaination
Explanation:
class MagicSquare():
def __init__(self,side):
self.side=side
self.two_dimension=[]
for row in range(1,side+1):
row_line=[]
for col in range(1,side+1):
row_line.append(0)
self.two_dimension.append(row_line)
def display(self):
row=0
col=int((self.side-1)/2)
for i in range(1,self.side**2+1):
self.two_dimension[row][col]=i
row-=1
col+=1
if row==-1:
row=self.side-1
if col==self.side:
col=0
if self.two_dimension[row][col]==0:
continue
else:
row+=1
if row==self.side:
row==0
for line in self.two_dimension:
for num in line:
print("{0:>3}".format(num),end=" ")
print()
def main():
for i in range(1,14,2):
square=MagicSquare(i)
square.display()
print("----------------------------------------------------")
if __name__ == '__main__':
main()
Answer: b. Códigos de comunicación/ comunication codes
Explanation:
Create the computer, network, and communication systems that an organization needs
