We are given that the
coordinates of the vertices of the rhombus are:
<span><span>A(-6, 3)
B(-4, 4)
C(-2, 3)
D(-4, 2)
To solve this problem, we must plot this on a graphing paper or graphing
calculator to clearly see the movement of the graph. If we transform this by
doing a counterclockwise rotation, then the result would be:
</span>A(-6, -3)</span>
B(-4, -4)
C(-2, -3)
D(-4, -2)
And the final
transformation is translation by 3 units left and 2 units down. This can still
be clearly solved by actually graphing the plot. The result of this
transformation would be:
<span>A′(6, -8)
B′(7, -6)
C′(6, -4)
D′(5, -6)</span>
You can add a lot of numbers (or so I think). One number I think you can add is 31.
352.7916667 or in another way 352.79
Answer:
z = 66
Step-by-step explanation:
RS = z
QT = z - 33
Based on the midsegment theorem, QT = ½(RS)
Plug in the values
z - 33 = ½(z)
Multiply both sides by 2
2(z - 33) = z
2z - 66 = z
Add 66 to both sides
2z = z + 66
Subtract z from both sides
2z - z = 66
z = 66
