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3 years ago

50 points! Solve the following systems of equations.

Mathematics

1 answer:

Tom [10]3 years ago

8 0

Answer: The answer is C.

Step-by-step explanation:

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What integer represents having 3dollars

sp2606 [1]

Answer:

-3 or -$3.

Step-by-step explanation:First, the set of integer numbers is the set of all the whole numbers (negatives, zero, and positives).

We want to write a $3 loss, now, the most important part here is that we have a loss, so we must represent this with a negative number

is -3 or -$3 (if we want to also respect the units)

7 0

3 years ago

Its only 13 14 15 and 16 thanks

PIT_PIT [208]

I could only answer 14. and it is 138.3

5 0

4 years ago

The function y = 8.5(1.1)x models the population in thousands of a town where x is the number of years after 2000. What will be

nikdorinn [45]

Answer:

The population will be at 65.45 in 2007.

Step-by-step explanation:

I graphed the equation below to find the answer.

If this answer is correct, please make me Brainliest!

6 0

4 years ago

The following shows the process a student used to determine the number of yards in 3,218 meters.

Yakvenalex [24]

I would say step 2 hope this helps

4 0

4 years ago

Read 2 more answers

Hello, help me please))

Fed [463]

Answer:

6
9
1/8
-10/11

Step-by-step explanation:

You can rewrite the given log expressions to express them in terms of ln(a), ln(b), and ln(c). Then substituting the given values will produce the value of the expression.

Or, you can define the variables 'a', 'b', and 'c' and let your calculator compute these directly.

$\ln\left(\dfrac{a^4}{b^4c^{-2}}\right)=4\ln(a)-(4\ln(b)-2\ln(c))=4\cdot2-4\cdot3+2\cdot5=\boxed{6}$

$\ln\left(\sqrt{b^{-2}c^4a^2}\right)=\dfrac{1}{2}\left(-2\ln(b)+4\ln(c)+2\ln(a)\right)=\ln(a)-\ln(b)+2\ln(c)\\\\=2-3+2\cdot5=\boxed{9}$

$\dfrac{\ln(a^1b^2)}{\ln(bc)^2}=\dfrac{\ln(a)+2\ln(b)}{(\ln(b)+\ln(c))^2}=\dfrac{2+2\cdot3}{(3+5)^2}=\dfrac{8}{64}=\boxed{\dfrac{1}{8}}$

$\ln(c^{-2})\left(\ln\dfrac{a}{b^{-3}}\right)^{-1}=\dfrac{-2\ln(c)}{\ln(a)-(-3)\ln(b)}=\dfrac{-2(5)}{2+3\cdot3}=\boxed{-\dfrac{10}{11}}$

_____

The applicable rules of logarithms are ...

ln(ab) = ln(a) +ln(b)
ln(a/b) = ln(a) -ln(b)
ln(a^b) = b·ln(a)
ln(a) = b ⇔ a = e^b

Of course, a square root is the same as a 1/2 power.

7 0

2 years ago