All categories

2 years ago

Which numbers have an absolute value of 4?(you can pick more than one) 4 -4 2 8

2 answers:

4 0

You can pick 4 and -4. Absolute value is the distance from 0 on a number line. So if I have a 2 on the number line, the amount of space from the 0 is 2. If I have a negative 9 on a number line then the absolute value is positive 9. A absolute value is always positive, even if the number is negative. Hope this helps!

oksian1 [2.3K]2 years ago

3 0

Answer:

4 and -4

Step-by-step explanation:

absolute value is always going to be positive and the overall value will only change if it is negative. so the "|4|" (absolute value of 4) is the same as "|-4|" (absolute value of negative 4)

You might be interested in

Which rectangle is similar to rectangle ABCD

omeli [17]

Answer:

JKLM is similar to ABCD

Step-by-step explanation:

5 0

2 years ago

The slope of the line tangent to the curve y^2 + (xy+1)^3 = 0 at (2, -1) is ...?

Lina20 [59]

$\frac{d}{dx}(y^2 + (xy+1)^3 = 0)
\\
\\\frac{d}{dx}y^2 + \frac{d}{dx}(xy+1)^3 = \frac{d}{dx}0
\\
\\\frac{dy}{dx}2y + \frac{d}{dx}(xy+1)\ *3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{d}{dx}(xy)+\frac{d}{dx}1\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{d}{dx}xy+x\frac{d}{dx}y+\frac{dx}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{dx}{dx}y+x\frac{dy}{dx}+\frac{dx}{dx}0\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0$
$\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(3y+3x\frac{dy}{dx}\right) (xy+1)^2 = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) (xy+1)^2 = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + 3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y') = 0
\\
\\3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y'+2yy' ) = 0
\\
\\y'(3x +6x^2y+3x^2y+2y ) = -3x^2y^3 -6xy^2-3y

$
$y' = \frac{-3x^2y^3 -6xy^2-3y}{(3x +6x^2y+3x^2y+2y )};\ x=2,y=-1
\\
\\y' = \frac{-3(2)^2(-1)^3 -6(2)(-1)^2-3(-1)}{(3(2) +6(2)^2(-1)+3(2)^2(-1)+2(-1) )}
\\
\\y' = \frac{-3(4)(-1) -6(2)(1)+3}{(6 +6(4)(-1)+3(4)(-1)-2 )}
\\
\\y' = \frac{12 -12+3}{(6 -24-12-2 )}
\\
\\y' = \frac{3}{( -32 )}$

7 0

3 years ago

Jackie works at two different jobs so she can buy a new car. She makes $15 per hour at her first job and $12 per hour at her sec

Inessa05 [86]

Answer:

Step-by-step explanation:

Step-by-step explanation:

$15x8=$120 = money earned at first job

$12x3=$36 = money earned at second job

$120+$36=$156 =total earned

7 0

2 years ago

Plz help with math homework

Mkey [24]

Where is the question. though

6 0

3 years ago

Harper has $14 in her piggy bank. Her mom pays her $12 for chores. How much does Harper now have in the piggy bank?

vovikov84 [41]

Answer:

Step-by-step explanation:

14+12=26

1+1=2

4+2=6

7 0

3 years ago

Read 2 more answers