1. The fractions shown are 3/4 and 6/8.
2. The multiplier is 2.
3. The fractions shown are 12/18 and 4/6
4. The divisor is 3.
The sum means addition.
Add the like terms together.
4x^3+2x^2-4x+3
+ 7x^3-4x^2+7x+8
4x^3 + 7x^3 = 11x^3
2x^2 + -4x^2 = -2x^2
-4x +7x = 3x
3 +8 = 11
The answer is : 11x^3 - 2x^2 + 3x + 11
For two complex numbers
![z_1=re^{i\theta}=r(\cos\theta+i\sin\theta)](https://tex.z-dn.net/?f=z_1%3Dre%5E%7Bi%5Ctheta%7D%3Dr%28%5Ccos%5Ctheta%2Bi%5Csin%5Ctheta%29)
and
![z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi)](https://tex.z-dn.net/?f=z_2%3Dse%5E%7Bi%5Cvarphi%7D%3Ds%28%5Ccos%5Cvarphi%2Bi%5Csin%5Cvarphi%29)
, the product is
![z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))](https://tex.z-dn.net/?f=z_1z_2%3Drse%5E%7Bi%28%5Ctheta%2B%5Cvarphi%29%7D%3Drs%28%5Ccos%28%5Ctheta%2B%5Cvarphi%29%2Bi%5Csin%28%5Ctheta%2B%5Cvarphi%29%29)
That is, you multiply the moduli and add the arguments. You have
![z_1=7e^{i40^\circ}](https://tex.z-dn.net/?f=z_1%3D7e%5E%7Bi40%5E%5Ccirc%7D)
and
![z_2=6e^{i145^\circ}](https://tex.z-dn.net/?f=z_2%3D6e%5E%7Bi145%5E%5Ccirc%7D)
, so the product is
Answer:
$450
Step-by-step explanation:
A way to find the median of a set of numbers is by listing each number one by one and then slowly crossing out the smallest and biggest number one by one. If you end up with two numbers left, then you take the mean of those numbers. To do that, you add the two numbers and divide it by two.