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3 years ago

Choose the best estimate for the mass of an apple

Mathematics

2 answers:

Sophie [7]3 years ago

8 0

Gotchu cuh. It’s 250g. This math stuff too easy

Alexandra [31]3 years ago

7 0

Answer:

25 or 250 i would go wit 250 but i fr dont know

Step-by-step explanation:

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The Patel family made a 6-pound turkey for dinner. If each person will eat 1/2 of a pound, how many people will it take to finis

Olin [163]

Answer:

12 people.

Step-by-step explanation:

Altogether, the Patel family has a 6-pound turkey. One person equals half a pound.

Thus,

It is 6-pound divided by 1/2, equaling 12.

8 0

2 years ago

Read 2 more answers

Estimate the solution for 632.97

kicyunya [14]

Answer: Estimation of the solution for 632.97 = 633.

Step-by-step explanation:

Since we have given that

$632.97$

First we estimate nearest to ones ,

So, since it has 9 in tenths place that is greater than 5

So, According to rule of estimation,

1 is getting added to the ones digit

So, after estimation, it becomes 633.

Hence, Estimation of the solution for 632.97 = 633.

5 0

4 years ago

An=5-6n fifth term and sum of first three terms

Korolek [52]

Answer:

5th term is -25

and sum of first three terms is -21

Step-by-step explanation:

We are given the sequence:

$\displaystyle \large{a_n = 5 - 6n}$

To find 5th term, substitute n = 5.

$\displaystyle \large{a_5 = 5 - 6(5)} \\ \displaystyle \large{a_5 = 5 - 30} \\ \displaystyle \large{a_5 = - 25}$

Therefore, fifth term is 25.

Next, to find the sum of first three terms, we will introduce sigma.

$\displaystyle \large{a_1 + a_2 + a_3 + ... + a_n = \sum_{k = 1}^{n} a_k}$

Our ak is 5-6k

Since we want to find sum of first three terms:-

$\displaystyle \large{ \sum_{k = 1}^{3}( 5 - 6k)}$

Expand Sigma in.

$\displaystyle \large{ \sum_{k = 1}^{3} 5 + \sum_{k = 1}^{3}- 6k}$

Property of Summation

$\displaystyle \large{ \sum_{k = 1}^{n} m = m \times n \: \: \: \sf{(m \: \: is \: \: constant})} \\ \displaystyle \large{\sum_{k = 1}^{n}(a_k + b_k) = \sum_{k = 1}^{n}a_k + \sum_{k = 1}^{n}b_k} \\ \displaystyle \large{\sum_{k = 1}^{n}ma_k =m\sum_{k = 1}^{n} a_k \: \: \: \sf{(m \: \: is \: \: constant})}$

Therefore:-

$\displaystyle \large{ \sum_{k = 1}^{3} 5 + \sum_{k = 1}^{3}- 6k} \\ \displaystyle \large{ (5 \times 3) - 6\sum_{k = 1}^{3}k} \\ \displaystyle \large{ 15 - 6\sum_{k = 1}^{3}k}$

Summation Formula

$\displaystyle \large{ \sum_{k = 1}^{n}k = \frac{1}{2} n(n + 1) }$

Thus:-

$\displaystyle \large{ 15 - 6\sum_{k = 1}^{3}k} \\ \displaystyle \large{ 15 - 6( \frac{1}{2}(3)(3 + 1) } \\ \displaystyle \large{ 15 - 6( \frac{1}{2}(3)(4)) } \\\displaystyle \large{ 15 - 6(3)(2 )} \\\displaystyle \large{ 15 - 6(6)} \\ \displaystyle \large{ 15 -36 = - 21 }$

7 0

3 years ago

Please help me correct my answers!! im really confused

Cerrena [4.2K]

Answer:

84°

Step-by-step explanation:

5 0

3 years ago

Find the equation for the circle with a diameter whose endpoints are (-5, -3) and (3,2).

densk [106]

Answer:

(x +1)^2 +(y +0.5)^2 = 22.25

Step-by-step explanation:

The center of the circle is the midpoint of the diameter, so is ...

(h, k) = ((-5, -3) +(3, 2))/2 = (-5+3, -3+2)/2 = (-1, -1/2)

The circle formula is then ...

(x -h)^2 +(y -k)^2 = r^2

(x -(-1))^2 +(y -(-1/2))^2 = r^2

We can find r^2 by substituting one of the points for (x, y).

(3 +1)^2 +(2 +1/2)^2 = r^2 = 16 +6.25 = 22.25

Then the circle equation is ...

(x +1)^2 +(y +0.5)^2 = 22.25

3 0

3 years ago