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Evgen [1.6K]
3 years ago
12

Is 400 pt greater than 100 gal

Mathematics
2 answers:
Rufina [12.5K]3 years ago
4 0

Answer:

no.400pts is equal to 50 gallons.1pt equals 0.125 gallons 400 pints x0.125 gallons equals 50 gallons,so that statement is false

Step-by-step explanation:

Y_Kistochka [10]3 years ago
3 0

The answer is false

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X+2y=-8 find the slope ​
laila [671]

Answer:

 Slope = -1.000/2.000 = -0.500

 x-intercept = -8/1 = -8.00000

 y-intercept = -8/2 = -4

Step-by-step explanation:

Step  1  :

Equation of a Straight Line

Graph of a Straight Line

Calculate the Y-Intercept

Calculate the Slope

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<em><u>Answer: </u></em>Slope = -1.000/2.000 = -0.500

<em><u>Hope this helps.</u></em>

7 0
3 years ago
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A company earns a weekly profit of P dollars by selling x items, according to the equation P(x)=-5x^2+40x-300. How many items do
STALIN [3.7K]
Since the equation is:

<span>P(x)=-5x^2+40x-300

Solving the equation by using the calculator, the values for x are:

x = 4.72

Therefore, the company must sell 8 items per week to maximize the profit.

</span>I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
3 0
3 years ago
Write the sum of 18+27 as the product of their gcf and another sum
Serjik [45]

One <em>possible answer</em> is:

9×(2+3)

Explanation:

First we find the sum of 18 and 27. 18+27 = 45.

Next we find the GCF of 18 and 27. We do this by finding the prime factorization of each:

18 = 2*9

9 = 3*3

Thus, 18 = 2*3*3.

27 = 3*9

9 = 3*3

Thus, 27 = 3*3*3

We want the common factors; there are 2 3's in common, so 3*3 = 9 is the GCF. This makes the product 9×( ). The missing number would be 5, since 9*5 = 45. Writing this as a sum, we can use 2+3; this gives us 9×(2+3).

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3 years ago
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PLEASE HELP ME WITH THIS PROBLEM AND EXPLAIN HOW YOU GOT THE ANSWER!?!?
Advocard [28]
4:10 pm ....................................
7 0
3 years ago
Three machines A, B, and C produce 55%, 25% and 20% respectively. The percentages of defective output are 3.5%, 4.5% and 5.5%. I
pishuonlain [190]

We are given the following information concerning the three production machines;

\begin{gathered} Of\text{ the total production;} \\ A=55\text{ \%}=0.55 \\ B=25\text{ \%}=0.25 \\ C=20\text{ \%}=0.20 \end{gathered}

Also, we are given the percentage of defective output as follows;

\begin{gathered} A=3.5\text{ \%}=0.035 \\ B=4.5\text{ \%}=0.045 \\ C=5.5\text{ \%}=0.055 \end{gathered}

Therefore, if an item is selected randomly, the probability that the item is defective would be;

\begin{gathered} P\lbrack defective\rbrack=(0.55\times0.035)+(0.25\times0.045)+(0.20\times0.055) \\ P\lbrack\text{defective\rbrack}=0.01925+0.01125+0.011 \\ P\lbrack\text{defective\rbrack}=0.0415 \end{gathered}

ANSWER:

The probability that the item is defective would be 0.0415

6 0
1 year ago
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