Answer:
Glomerular Hydrostatic pressure
.
Explanation:
The basic function of the kidney is the formation of urine for elimination through the urinary excretory system. Two different processes determine this formation: the filtration of fluid through the glomerular capillaries into Bowman's space and the modification of the volume and composition of the glomerular filtrate in the renal tubules. The fluid passes from the glomerular capillaries to Bowman's capsule due to the existence of a pressure gradient between these two areas. This process is favored by two structural characteristics that make renal corpuscles particularly effective filtration membranes: glomerular capillaries have a much higher number of pores than other capillaries, and the efferent arteriole has a smaller diameter than the afferent arteriole, causing greater resistance to outflow of blood flow from the glomerulus and increasing glomerular hydrostatic pressure. Increased glomerular hydrostatic pressure (due to increased blood flow through the glomerulus) increases filtration, while increases in Bowman's hydrostatic pressure or urinary space (which remains constant, unless there is disease at that level, usually due to fibrosis) and plasma P. oncotic (determined by proteins, which tend to "drag" plasma into the glomerulus) decrease filtering. Resulting in a filtering pressure of 10 mmHg.
<span>The thing that might happen to the tree was it might get swept away by the current until it catches on something or disappears (dissolves). The tree will going to the flow of the river until it catches on something where it may disappears or dissolve.</span>
Answer:Planarians = flatworms
Marine worms = segmented worms
Pinworms = roundworms
Tapeworms = flatworms
Explanation:
I’m Built Different
Answer:
Yes
Explanation:
Range rule of thumb predicts the Range to be a multiple of 4 of the standard deviation or to be four times the standard deviation. Making the usual values equal to 2 standard deviations distanct of the mean of the data distribution.
In a given distribution with mean and standard deviation that is obtained, the usual values in mean (as seen in the attached image).
2*standard deviation and mean + 2*standard deviation.
If the data point is not up to the mean
- 2* standard deviation is taken to be significantly low.
If the data point is more than the mean
+ 2*standard deviation is taken to be significantly high.
Let's take the xbar to be the mean and s as standard deviaiton
Given,
mean, xbar = 1116.2
standard deviation, s =127.7
The range rule of thumb shows that the usual values are within 2 standard deviations from the mean
Lower boundary
= xbar - 2s
= 1116.2 - 2(127.7)
= 860.8
Upper boundary
= xbar + 2s
= 1116.2 + 2(127.7)
= 1371.6
We should note that 1411.6 is not between 860.8 and 1371.6, which connotes that 1411.6cm^3 is unusually high.