Question

During an airplanes ascent, the plane reaches a horizontal distance from the airport of 1 km and then 7 km. The plane ascends at a slope of 2/3. Find the vertical distance (y) in feet that the plane traveled during the indicated spots

Answer 1

Answer:

The vertical distance in feet that the plane traveled was 4 Km

Step-by-step explanation:

The Slope of a Line

Suppose we know a line passes across points A(x1,y1) and B(x2,y2). The slope can be calculated with the equation:

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

The airplane ascent will be modeled with the equation of a line because we are given a constant slope of m=2/3. We also know the horizontal distances are x1=1 Km and x2=7 Km. Substituting in the formula above:

$\displaystyle \frac{2}{3}=\frac{y_2-y_1}{7-1}$

Operating:

$\displaystyle \frac{2}{3}=\frac{y_2-y_1}{6}$

Solving for y2-y1, we get the vertical distance traveled by the plane:

$\displaystyle y_2-y_1=6*\frac{2}{3}=4$

Thus, the vertical distance in feet that the plane traveled was 4 Km