Answer:
- vertical scaling by a factor of 1/3 (compression)
- reflection over the y-axis
- horizontal scaling by a factor of 3 (expansion)
- translation left 1 unit
- translation up 3 units
Step-by-step explanation:
These are the transformations of interest:
g(x) = k·f(x) . . . . . vertical scaling (expansion) by a factor of k
g(x) = f(x) +k . . . . vertical translation by k units (upward)
g(x) = f(x/k) . . . . . horizontal expansion by a factor of k. When k < 0, the function is also reflected over the y-axis
g(x) = f(x-k) . . . . . horizontal translation to the right by k units
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Here, we have ...
g(x) = 1/3f(-1/3(x+1)) +3
The vertical and horizontal transformations can be applied in either order, since neither affects the other. If we work left-to-right through the expression for g(x), we can see these transformations have been applied:
- vertical scaling by a factor of 1/3 (compression) . . . 1/3f(x)
- reflection over the y-axis . . . 1/3f(-x)
- horizontal scaling by a factor of 3 (expansion) . . . 1/3f(-1/3x)
- translation left 1 unit . . . 1/3f(-1/3(x+1))
- translation up 3 units . . . 1/3f(-1/3(x+1)) +3
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<em>Additional comment</em>
The "working" is a matter of matching the form of g(x) to the forms of the different transformations. It is a pattern-matching problem.
The horizontal transformations could also be described as ...
- translation right 1/3 unit . . . f(x -1/3)
- reflection over y and expansion by a factor of 3 . . . f(-1/3x -1/3)
The initial translation in this scenario would be reflected to a translation left 1/3 unit, then the horizontal expansion would turn that into a translation left 1 unit, as described above. Order matters.
Answer:
y₀.₉₅ = 3659
Step-by-step explanation:
P( no accident ) = 0.8
P( one accident ) = 0
deductible = 500
mean = 3000
<u>Determine the 95th percentile of the insurance company payout </u>
Assuming : y =company payout , x =amount of loss incurred due to accident
Then :
P( x < 500 ) = 0.2 ( 1 - e^-500/3000)
= 0.2 ( 1 - e^-1/6 )
95th percentile =
= P( y < y₀.₉₅ ) 0.95
P( y = 0 ) = 0.8 + 0.2 ( 1 - e^-1/6 ) = 0.8307
attached below is the remainder of the solution
You mean (x-8)/3 = 3 ...right?
You would multiply both sides by 3.
Then, add 8 to both sides.
x=17
Answer:
Albert = $2159.07; Marie = $2244.99; Hans = $2188.35; Max = $2147.40
Marie is $10 000 richer
Step-by-step explanation:
Albert
(a) $1000 at 1.2 % compounded monthly
A = 1000(1 + 0.001)¹²⁰ = $1127.43
(b) $500 losing 2%
0.98 × 500 = $490
(c) $500 compounded continuously at 0.8%
(d) Balance
Total = 1127.43 + 490.00+ 541.64 = $2159.07
Marie
(a) 1500 at 1.4 % compounded quarterly
A = 1500(1 + 0.0035)⁴⁰ = $1724.99
(b) $500 gaining 4 %
1.04 × 500 = $520.00
(c) Balance
Total = 1724.99 + 520.00 = $2244.99
Hans
$2000 compounded continuously at 0.9 %
Max
(a) $1000 decreasing exponentially at 0.5 % annually
A = 1000(1 - 0.005)¹⁰= $951.11
(b) $1000 at 1.8 % compounded biannually
A = 1000(1 + 0.009)²⁰ = $1196.29
(c) Balance
Total = 951.11 + 1196.29 = $2147.40
Marie is $ 10 000 richer at the end of the competition.
Answer:
In the first week, Micah bought 11 gallons of gas.
In the second week, Micah bought 8 gallons of gas.
Step-by-step explanation:
Given:
First week
x gallons of gas at $2.39 per gallon
x gallons = $2.39x
Second week
3 fewer gallons of gas than the first week at $2.49 per gallon
x - 3 gallons = $2.49(x-3)
Total spent = $46.21
$2.39x + $2.49(x-3) = $46.21
2.39x + 2.49x - 7.47 = 46.21
4.88x - 7.47 = 46.21
Add 7.47 to both sides
4.88x - 7.47 + 7.47 = 46.21 + 7.47
4.88x = 53.68
Divide both sides by 4.88
x = 53.68/4.88
= 11
x = 11
First week = x = 11 gallons
Second week
= x - 3
= 11-3
= 8 gallons
Therefore,
In the first week, Micah bought 11 gallons of gas.
In the second week, Micah bought 8 gallons of gas.