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3 years ago

What’s measure angle K ?

Mathematics

2 answers:

Norma-Jean [14]3 years ago

6 0

Answer:

angle K = 180 - 128 = 52 degrees

Step-by-step explanation:

8090 [49]3 years ago

5 0

The sum of all angles in a triangle will always add up to 180°. So, because the two triangles are identical, you can do 180-46-82, and get your answer, which is 52°. Have a nice day!

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PLEASE HELP ME!!! 10 POINTS!!!

Svetach [21]

Answer:

A. Fun at the water park

Step-by-step explanation:

The definition of opportunity cost is "the loss of potential gain from other alternatives when one alternative is chosen" - oxford dictionary.

Since Hugo is giving up a fun day at the water park, that is what he is missing aka his opportunity cost

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2 years ago

Which equation finds the volume of a cube with a side length of 2n6 units?

Xelga [282]

Answer:

Volume of the cube = (2n6)³

Step-by-step explanation:

Volume of a cube = L*B*H

Volume of a cube= L*L*L=L³ (since all the sides of the cube are equal.

Volume of the cube = (2n6)³

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3 years ago

What is the product of (1.9*10^-3)(2*10^4)

RoseWind [281]

Answer:

to solve use the distributive property and multiply

Step-by-step explanation:

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3 years ago

Read 2 more answers

24÷(−4)+(−2)⋅(−5)= who wants to get brain list if you explain nd answer

Tatiana [17]

Answer:

Step-by-step explanation:

24÷(-4)+(-2)·(-5)

-6+(-2)·(-5)

-6+10

8 0

3 years ago

The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth

Art [367]

Answer:

a) $N_0=250\; k=0.15$

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies $t=0$ . And $N(0)=N_0$ . The process is:

$N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250$

b) After 2 days means $t=48$ . So, we just replace and operate:

$N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}$

c) $N(t_1)=4000; \;t_1=?$

$N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\ \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h$

d) $t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)$

$N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h$

6 0

3 years ago