1)inside the triangule is 180º .There are 3 angules, one with 120º, theta and
angle ACB, lets call it x.
x + theta + 120 = 180
x + theta= 180-120
x + theta= 60
x= 60- theta
angle ACB= 60- theta
I'm sorry this is gauge is there anymore info
15 i am pretty sure i’m probably gonna be wrong
Answer:
B 10.8 or
A 9.2 depending on what side of the triangle is "x".
Step-by-step explanation:
we cannot see the triangle and which side is which. you forgot to show us the picture (or describe it in more detail).
but I assume that "x" would be the Hypotenuse (the baseline of the right triangle, the side opposite of the 90 degree angle).
then by using Pythagoras
c² = a² + b²
=>
x² = 10² + 4² = 116
x = sqrt(116) = 10.8
but if x is any of the other sides (and not the Hypotenuse), then you need to adapt the calculation.
for example, if the Hypotenuse is the side with 10, then Pythagoras' formula would look like this
10² = x² + 4²
x² = 10² - 4² = 84
x = sqrt(84) = 9.2 (and answer A would be correct).
or if the Hypotenuse is the side with 4, then
4² = x² + 10²
x² = 4² - 10² = -84
x = sqrt(-84)
and that did not make any sense for real distances. so, this configuration is actually impossible for a right triangle.
