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3 years ago

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PLEASE HELP ME!!! 10 POINTS!!!

1 answer:

Svetach [21]3 years ago

5 0

Answer:

A. Fun at the water park

Step-by-step explanation:

The definition of opportunity cost is "the loss of potential gain from other alternatives when one alternative is chosen" - oxford dictionary.

Since Hugo is giving up a fun day at the water park, that is what he is missing aka his opportunity cost

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Write a differential equation that models the given situation. The stated rate of change is with respect to time t. (Use k for t

Alex787 [66]

The differential equation that models the given situation will be dy/dt = K(N - y).

<h3>How to compute the equation?</h3>

Let y = number of individuals who have heard about the product.

Let N - y = this who haven't heard about the product.

From the given statement, the rate for change will be t = dy/dt. Therefore, the differential equation that models the given situation will be dy/dt = K(N - y).

Learn more about equations on:

brainly.com/question/2972832

#SPJ1

3 0

2 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.

konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

$BC^2=BD\cdot AB.$

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

$x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.$

Take positive value x. You get

$AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.$

2. According to the previous theorem,

$AC^2=AD\cdot AB.$

Then

$AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

Answer: $AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

$CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D$

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0

3 years ago

Read 2 more answers

The function C (t) = StartFraction 4 t Over t squared + 2 EndFraction models the cost per student of a field trip when x student

Vika [28.1K]

Answer:

It is vertically stretched by a factor of 200 and shifted 10 units up.

Step-by-step explanation:

cool like that

3 0

2 years ago

Read 2 more answers

Equation: –4x – 5 + 2x = –11

BaLLatris [955]

<h2><u>ANSWER </u></h2>

x= 3

Step-by-step explanation:

=> -4x – 5 + 2x = -11

=> -2x = -11+5

=> -2x = -6

=> x= 6/2

=> x= 3

5 0

2 years ago

Read 2 more answers

What is the equation of the line perpendicular to y=2x+3.14 going through the points (2,4)?

inessss [21]

Answer:

$x+2y-10=0$

Step-by-step explanation:

Consider an equation: $y=mx+c$

Here, m is the slope of the line and c is the y-intercept.

Given equation is $y=2x+3.14$

Here, slope is $m=2$

As product of slopes of two perpendicular lines is equal to $-1$ , slope of the required line is $m_1=\frac{-1}{m}=\frac{-1}{2}$ .

Let $(x_1,y_1)=(2,4)$

Equation of the required line is $y-y_1=m_1(x-x_1)$

$y-4=\frac{-1}{2}(x-2)\\2(y-4)=-1(x-2)\\2y-8=-x+2\\x+2y-8-2=0\\x+2y-10=0$

8 0

3 years ago