Answer:
306.8 feet
Step-by-step explanation:
Refer the attached figure .
A surveyor moves 160 feet away from the base of the pole i.e. ED = 160 m
Referring the image .
AC=ED=160 m
A transit i.e. AE is 6 feet tall.
AE = CD=6 feet
With a transmit the angle of elevation to the top of the pole to be 62° i.e. ∠BAC = 62°
To Find BC , use tigonometric ratio.
Now, the height of the pole = BC+CD =300.8+6=306.8 feet
Hence the height of the pole is 306.8 feet
Area of the polygon defined by the given points is 62.5 sq units
Step-by-step explanation:
Step 1 :
Let P be the point (-5,0) Q = (0,-5), R = (-15,-20) and S = (20,-15)
We have to to find the area of the polygon PQRS
Step 2 :
The area of polygon given the vertices (x is given by
Area = mod ( ) ÷ 2
Where is the vertex n's x coordinate ,
is the vertex n's y coordinate
Substituting the corresponding values ,
Area of PQRS = mod ( (25 - 0)+ (0-75) +(300-300) +( 0-75) ) ÷ 2
= mod (25-75+0-75) ÷ 2
= mod (-125) ÷ 2 = 125 ÷ 2 = 62.5 sq units
Step 3 :
Answer :
Area of the polygon defined by the given points is 62.5 sq units
9514 1404 393
Answer:
(x, y) = (5, -4)
Step-by-step explanation:
The Desmos graphing calculator is a handy tool for solving questions like this one. It tells you the solution is ...
(x, y) = (5, -4)
