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3 years ago

Which ordered pair lies on the function f(x) = x^2 + 3?

Mathematics

1 answer:

AfilCa [17]3 years ago

5 0

B lies on the function

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Find the product 4×6×50 tell what strategy you used

Brut [27]

Answer:

1200

Step-by-step explanation:

4x6= 24

24x 5= 120

120x 10= 1200

5 0

3 years ago

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A quadratic function is a function of the form y=ax^2+bx+c where a, b, and c are constants. Given any 3 points in the plane, the

pochemuha

Answer:

The quadratic function whose graph contains these points is $y=-x^{2}-2x-2$

Step-by-step explanation:

We know that a quadratic function is a function of the form $y=ax^{2}+bx+c$ . The first step is use the 3 points given to write 3 equations to find the values of the constants a,b, and c.

Substitute the points (0,-2), (-5,-17), and (3,-17) into the general form of a quadratic function.

$-2=a*0^{2}+b*0+c\\c=-2$

$-17=a*-5^{2}+b*-5+c\\c=-25a+5b-17$

$-17=a*3^{2}+b*3+c\\ c=-9a-3b-17$

We can solve these system of equations by substitution

Substitute $c=-9a-3b-17$

$-9a-3b-17=25a+5b-17\\-9a-3b-17=-2$

Isolate a for the first equation

$-9a-3b-17=-25a+5b-17\\a=\frac{b}{2}$

Substitute $a=\frac{b}{2}$ into the second equation

$-9\left(-\frac{b}{2}\right)-3b-17=-2$

Find the value of b

$-9\left(-\frac{4b}{17}\right)-3b-17=-2\\ b=-2$

Find the value of a

$a=\frac{b}{2}\\ a=-1$

The solutions to the system of equations are:

b=-2,a=-1,c=-2

So the quadratic function whose graph contains these points is

$y=-x^{2}-2x-2$

As you can corroborate with the graph of this function.

8 0

3 years ago

Write the fractional notation in lowest terms. 110 minutes to 4 hours.

Angelina_Jolie [31]

It will be 27 mins to 2 hours I think

5 0

2 years ago

Write 480,000 in scientific notation.

emmasim [6.3K]

Answer:

4.8 × 10^5

Step-by-step explanation:

3 0

2 years ago

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Fake Question: Should Ujalakhan01 be a moderator? (If you could answer I'd appreciate it haha.)

Dovator [93]

Answer:

$a^9 + b^ 5 + c^{13}$

Step-by-step explanation:

$(a^5 \times a^4)+(b^2 \times b^3) + (c^7 \times c^6)$

When bases are same and it is multiplication, then add the exponents.

$(a^{5+4})+(b^{2+3})+(c^{7+6})$

$(a^9)+(b^ 5) + (c^{13})$

Apply rule : $(a^b)=a^b$

$a^9 + b^ 5 + c^{13}$

8 0

3 years ago

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