Answer:
24.2 B
Step-by-step explanation:
This is right on edge
No, it would end up being 20a-32 which is not equivalent to 12a-6
<span>Percent of discount is 25% and the sale price is 40$ what is the original amount? $160
percent of discount is 5% and the sale price is 57$ what is the original amount? $60
percent of discount is 80% and the sale price is 90$ what is the original amount? $112.5
percent of discount is 15% and the sale price is 146.54$ what is the original
amount? $976.93
the original price is 60$ and the sale price is 45$ what is the percent of discount? 25%
original price is 82$ and the sale price is 65.60$ what is the percent of discount? 20%
original price is 95$ and the sale price is 61.75$ what is the percent of discount? 35%</span>
Answer: 
Required theorem:
Pythagorean theorem = 
In other words, one side length squared + another side length squared = the middle lined squared.
Step-by-step explanation:
We can only have a positive distance so your final answer is :
Answer:
![\frac{2c}{3x^2c}+ \frac{36x^3c}{3x^2c} +\frac{24x^2}{3x^2c} [\tex]Step-by-step explanation:We need to find sum of 2 / 3x^2 +12x and 8 / cSo, solving:[tex](\frac{2}{3x^2} + 12 x ) +\frac{8}{c}](https://tex.z-dn.net/?f=%5Cfrac%7B2c%7D%7B3x%5E2c%7D%2B%20%5Cfrac%7B36x%5E3c%7D%7B3x%5E2c%7D%20%2B%5Cfrac%7B24x%5E2%7D%7B3x%5E2c%7D%20%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3EWe%20need%20to%20find%20sum%20of%202%20%2F%203x%5E2%20%2B12x%20and%208%20%2F%20c%3C%2Fp%3E%3Cp%3ESo%2C%20solving%3A%3C%2Fp%3E%3Cp%3E%5Btex%5D%28%5Cfrac%7B2%7D%7B3x%5E2%7D%20%2B%2012%20x%20%29%20%2B%5Cfrac%7B8%7D%7Bc%7D)
Taking LCM of 3x^2 and 1 i.e. 3x^2
