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12345 [234]
3 years ago
10

Find the unit rate 5 cars for 20 people

Mathematics
1 answer:
ololo11 [35]3 years ago
3 0

Answer:

4 people per car

Step-by-step explanation:

To find the unit rate we would have to do

20/5=4

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If you have $ twentyfive of quarters and dimes how much quarters and dimes do u have
mamaluj [8]

You have 400 quarters and 1,000 dimes.

For example you have four quarters in a dollar so you multiply 4*100 = 400.

For example you have ten dimes in a dollar so you multiple 10*100 = 1,000

Hope this helps!!!!!!

Please give me brainliest!!!!!!

6 0
3 years ago
What is the factorization of the trinomial -x2 - 2x +48​
Whitepunk [10]

The answer will be 48x

5 0
4 years ago
What is the recursive formula when given the explicit formula for the following geometric sequence?
satela [25.4K]

Answer:

C

Step-by-step explanation:

Take a careful look at a(n) =  6(-8)^(n-1).

The first term is 6.  This is the result if we let n = 1; 6(-8)^0 = 6(1) = 6.  Thus, we can immediately eliminate possible answer choices A and D.

What's the next term?  Knowing that the first term, a(1), is 6, the next term is found by multiplying this 6 by (-8)^1, obtaining -48.

The next (third) term is found by multiplying this -48 by (-8)^2, obtaining -48*(+64), or - 3072.

Note that the sign of (-8)^(n-1) alternates, being odd when n-1 is odd and even when n-1 is even.

Answer C is the correct one.  

5 0
4 years ago
Evaluate f (2) if f (x)= 10-x^3
weeeeeb [17]
<span> f (x)= 10-x³. 
f(2) means the value of the function when x=2.
So, we need to substitute 2 instead of x.

f(2) = 10 - 2³ = 10-8 =2

f(2) = 2


</span>
7 0
4 years ago
Consider the line integral Z C (sin x dx + cos y dy), where C consists of the top part of the circle x 2 + y 2 = 1 from (1, 0) t
pashok25 [27]

Direct computation:

Parameterize the top part of the circle x^2+y^2=1 by

\vec r(t)=(x(t),y(t))=(\cos t,\sin t)

with 0\le t\le\pi, and the line segment by

\vec s(t)=(1-t)(-1,0)+t(2,-\pi)=(3t-1,-\pi t)

with 0\le t\le1. Then

\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)

=\displaystyle\int_0^\pi(-\sin t\sin(\cos t)+\cos t\cos(\sin t)\,\mathrm dt+\int_0^1(3\sin(3t-1)-\pi\cos(-\pi t))\,\mathrm dt

=0+(\cos1-\cos2)=\boxed{\cos1-\cos2}

Using the fundamental theorem of calculus:

The integral can be written as

\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)=\int_C\underbrace{(\sin x,\cos y)}_{\vec F}\cdot\underbrace{(\mathrm dx,\mathrm dy)}_{\vec r}

If there happens to be a scalar function f such that \vec F=\nabla f, then \vec F is conservative and the integral is path-independent, so we only need to worry about the value of f at the path's endpoints.

This requires

\dfrac{\partial f}{\partial x}=\sin x\implies f(x,y)=-\cos x+g(y)

\dfrac{\partial f}{\partial y}=\cos y=\dfrac{\mathrm dg}{\mathrm dy}\implies g(y)=\sin y+C

So we have

f(x,y)=-\cos x+\sin y+C

which means \vec F is indeed conservative. By the fundamental theorem, we have

\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)=f(2,-\pi)-f(1,0)=-\cos2-(-\cos1)=\boxed{\cos1-\cos2}

3 0
3 years ago
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