Answer:
5,040 different passwords are possible
Step-by-step explanation:
Assuming that 4-digit means using only numeric values.
This is a permutations problem.
n = number of values used with number values only this is 10
r = the number used in each case without repeating in this case 4
nPr = n! / (n - r)!
nPr = 10! / (10-4)!
nPr = 10! / 6!
The ! means factorial. For example 4! = 4 x 3 x 2 x 1 = 24
A quick hack for dividing factorials is to use cancelling.
10! / 6! = 10 x 9 x 8 x 7 (because 6 to 1 are cancelled by 6!)
= 5040
So, we have
<span>Z=<span><span>x−μ / </span>σ
</span></span><span>Mean would be = 56
30 - 56 = |-26|
4
3 - 56 = |-13|
and
Standard deviation= 13
</span><span>2 - 1 will give us the approximate area
95/2 - 68/2 = N
95
-68 = 27
27 /2 = 13.5
</span>Hence, the answer would be
<span>800,000 * .135
</span>= <span> 108000</span>
Lets Sean's age be x
Helen's age by y
x/y=3/5
x=3/5y
Second equation
2(x-2)=y-2
on solving u get Helen as 10 and Sean as 6
In math, IS represents = OF represents multiply
1. So for the first problem is saying 24% * 80 24% is the same as .24 so .24*80=19.2
2. For this one the problem is saying 15=30%*x So for this we need to find x. So we divide both sides by .3 and get x = 50
3. You do the same thing as in 2. Im not gonna do all ur homework so you can do this one.
Hope that helps :)<span />
