Answer:
<em>The equation will be:
</em>
Step-by-step explanation:
The number of student tickets that were sold
and the number of other tickets that were sold 
Student tickets cost $3 a piece and tickets for everyone else cost $5 each.
So, <u>the total cost of</u>
<u>student tickets</u>
and <u>the total cost of</u>
<u>other tickets</u> 
Given that, the drama club sold <u>total $779 worth of tickets</u>.
So, the equation will be: 
Your answer will be choice A.
a = 15.1, b = 23.5, perimeter = 56.6
The function to the graph is 6
Answer:
All potential roots are 3,3 and
.
Step-by-step explanation:
Potential roots of the polynomial is all possible roots of f(x).

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.
p=All the positive/negative factors of 45
q=All the positive/negative factors of 3


All possible roots

Now we check each rational root and see which are possible roots for given function.




Similarly, we will check for all value of p/q and we get

Thus, All potential roots are 3,3 and
.
Multiplication because you are going to multiply the recipe by 2 to double it.