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tia_tia [17]
3 years ago
15

Write an equation for the amount of

Mathematics
1 answer:
emmasim [6.3K]3 years ago
3 0

Answer: 1,500 messages.

Step-by-step explanation: please give the crown.

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C + 6 &lt; 7<br> what’s the answer??
Marrrta [24]

Answer:

c<1

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Legalize Marijuana, Part II. As discussed in Exercise 6.12, the 2010 General Social Survey reported a sample where about 48% of
kvv77 [185]

Answer:

Around 2397 Americans must be surveyed to get a margin of error of 2%.

Step-by-step explanation:

We are given the following in the question:

Proportion of US residents who thinks marijuana should be made legal = 48%

\hat{p} = 0.48

We have to construct a 95% confidence interval.

Margin of error = 2% = 0.02

Formula for margin of error =

z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting values, we get,

0.02 = 1.96\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\0.02 = 1.96\times \sqrt{\dfrac{0.48(1-0.48)}{n}}\\\\\sqrt{n} = 1.96\times \dfrac{\sqrt{0.48(1-0.48)}}{0.02}\\\\\sqrt{n}=48.96\\n = 2397.0816\approx 2397

Thus, around 2397 Americans must be surveyed to get a margin of error of 2%.

8 0
3 years ago
Determine whether the series is convergent or divergent. 1 2 3 4 1 8 3 16 1 32 3 64 convergent divergent Correct:
Vanyuwa [196]

Answer:

This series diverges.

Step-by-step explanation:

In order for the series to converge, i.e. \lim_{n \to \infty} a_n =A it must hold that for any small \epsilon>0, there must exist n_0\in \mathbb{N} so that starting from that term of the series all of the following terms satisfy that  |a_n-A|n_0 .

It is obvious that this cannot hold in our case because we have three sub-series of this observed series. One of them is a constant series with a_n=1 , the other is constant with a_n=3 , and the third one has terms that are approaching infinity.

Really, we can write this series like this:

a_n=\begin{cases} 1 \ , \ n=4k+1, k\in \mathbb{N}_0\\ 2^{k}\ , \ n=2k, k\in \mathbb{N}_0\\3\ , \ n=4k+3, k\in \mathbb{N}_0\end{cases}

If we  denote the first series as b_n=1, we will have that \lim_{k \to \infty} b_k=1.

The second series is denoted as c_k=2^k and we have that \lim_{k \to \infty} c_k=+\infty.

The third sub-series d_k=3 is a constant series and it holds that \lim_{k \to \infty} d_k=3.

Since those limits of sub-series are different, we can never find such n_0\\ so that every next term of the entire series is close to one number.

To make an example, if we observe the first sub-series if follows that A must be equal to 1. But if we chose \epsilon =1, all those terms associated with the third sub-series will be out of this interval (A-1, A+1)=(0, 2).

Therefore, the observed series diverges.

5 0
4 years ago
okay so I don't really understand how to change a decimal to a fraction and the teacher never really explained it to us and she
Fofino [41]

\bf 0.2121\overline{21}\qquad \qquad \qquad x=0.2121\overline{21}\\\\ -------------------------------\\\\ \stackrel{\textit{moving the 21 to the left}}{\stackrel{100\cdot x}{100\cdot 0.2121\overline{21}}}\implies  21.2121\overline{21}\implies  \begin{array}{llll} 21&+&0.2121\overline{21}\\ 21&+&x \end{array} \\\\\\ therefore\qquad \qquad 100x  = 21+x\implies 99x=21 \\\\\\ x=\cfrac{21}{99}\implies x=\stackrel{simplified}{\cfrac{7}{33}}

5 0
3 years ago
Does this graph show a function explain how you know
In-s [12.5K]
<h3>Answer:</h3>

C. No, the graph fails the vertical line test

<h3>Step-by-step explanation:</h3>

Functions describe the relationship between the dependent variable, y, and the independent variable, x.

Functions

For a graph to be a function, x-values cannot repeat. This means that one x-value cannot have more than one y-value.

However, functions can have repeating y-values. So, y-values can have more than one x-value; as seen in quadratic functions. This means that answer B cannot be correct.

Vertical Line Test

The vertical line test is a way to determine if a graph is a function. A graph passes the vertical line test if you can draw a vertical line at every point on the coordinate plane and not have it intersect with the graph more than once.

On the graph in the question, a vertical line would intersect with the graph twice at the x-values greater than -1. Since the graph fails the vertical line test, it is not a function.

5 0
2 years ago
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