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telo118 [61]
3 years ago
10

A building with a cost of $1,800,000 has an estimated residual value of $125,000, has an estimated useful life of 40 years, and

is depreciated by the straight-line method. a. What is the amount of the annual depreciation?
Mathematics
1 answer:
nika2105 [10]3 years ago
5 0

Answer:

$41,875

<u>Extra</u>

a. $17,250 [($780,000 – $90,000) ÷ 40]

b. $366,000 [$780,000 – ($17,250 × 24 yrs.)]

c. $29,600 [($366,000 – $70,000) ÷ 10 yrs.]

Step-by-step explanation:

Step 1: Determine the cost of the asset

1,800,000

Step 2: Subtract the estimated salvage value of the asset from the cost of the asset to get the total depreciable amount

1,800,000 - 125,000

Step 3: Determine the useful life of the asset

40

Step 4: Divide the sum of step (2) by the number arrived at in step (3) to get the annual depreciation amount

$41,875

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Answer:

A

Step-by-step explanation:

A scale drawing is a reduced  or enlarged form in terms of dimensions of an original image / building / object

the scale drawing is usually reduced or enlarged at a constant dimension

scale of the drawing = original dimensions / dimensions of the scale drawing

a = 12 inches / 6 = 2 inches

b = 9 inches / 6 = 1.5 inches

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3 years ago
In "The Adventure of the Blue Carbuncle," what makes Sherlock Holmes certain that the owner of the hat and the goose will respon
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Let a "binary code" be the set of all binary words, each consisting of 7 bits (i.e., 0 or 1 digits). For example, 0110110 is a c
Dmitry_Shevchenko [17]

Answer:

a) 128 codewords

b) 35 codewords

c) 29 codewords

Step-by-step explanation:

a) Each 7 bits consist of 0 or 1 digits. Therefore the first bit is two choices (0 or 1), the second bit is also two choices (0 or 1), continues this way till the last bit.

So total number of different code words in 7 bits is 2×2×2×2×2×2×2 = 2⁷ = 128

There are 128 different codewords.

b) A code word contains exactly four 1's this means that  it has four 1's and three 0's . Therefore, in 7 bits, we have four of the same kind and three of the same kind. Hence, total number of code words containing exactly four 1's =7!/(4!*3!) = 35 codewords

c) number of code words containing at most two 1's  = codewords containing zero 1's + words containing one 1's + words containing two 1's

Now codewords containing zero 1's = 0000000 so 1 word

Codewords containing one 1's = 1000000,0100000,0010000,0001000,0000100,0000010,0000001. That's seven words

Codewords containing two 1's means word containing two 1's and five 0's. So out of seven, two are of one kind and five are of another kind

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Hence, codewords having at most two 1's = 21+7+1 =29 codewords

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3 years ago
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The income of the amusement park is a function of the price of the ticket

The entry price that will result in no income is $24

<h3>How to determine the entry price that results in no income</h3>

The expression for the income is given as:

96x - 4x^2

When the income is 0, we have the following equation

96x - 4x^2 = 0

Factor out 4x

4x(24 - x) = 0

Split the equation

4x = 0 or 24 - x = 0

Solve for x

x = 0 or x = 24

This means that, the entry price that will result in no income is $24

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Answer:

Answer below

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