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fredd [130]
3 years ago
10

Solve this system of eqations y= 2x x= -y+2x show work for full credit​

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
8 0

Answer:

x = 2/3

y = 4/3

Step-by-step explanation:

y = 2x    ----------------(I)

x = -y + 2      -----------------(II)

substitute y =2x in equation (II)

x = -2x + 2

x +  2x = 2

     3x = 2

      x = 2/3

Plugin x = 2/3 in equation (I)

y = 2 * \frac{2}{3}

y = 4/3

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viktelen [127]
Here is our profit as a function of # of posters
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Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10                         
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750

Correct answer is C)
</span>
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