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svetoff [14.1K]

3 years ago

12

X + 5y - 4z = 10 -* - y = -6 -6x+2y = -20

1 answer:

Brums [2.3K]3 years ago

8 0

Answer:

567

Step-by-step explanation:

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How many fractions are equalavent to 4/5.

Alexeev081 [22]

The list of equal fractions could be very long, but here are a few that are equal to 4/5.

4*2 = 8
5*2 = 10

8/10 = 4/5
64/80 = 4/5
16/20 = 4/5

3 0

3 years ago

The probability of randomly drawing a red card from a bag that contains red, blue, and green cards is 3/10. What is the probabil

Katarina [22]

If the probability of drawing a red card is 3/10, then if we take this fom a whole, 10/10, we can find the probability of not choosing a red card.
10/10-3/10=7/10

The probability of not drawing a red card is 7/10 or 70%.

7 0

3 years ago

PLEASE HELP ME ASAP ILL MARK BRIANLIEST!!!!!!!!! ANSWER THE QUESTIONS AND DO THE STEPS TOO PLEASEE

Anon25 [30]

Answer:

1). t ≥ - $\frac{3}{2}$

2). k ≥ $\frac{16}{3}$

3). y < - $\frac{1}{2}$

4). b > $\frac{250}{9}$

5). w ≤ 0

Step-by-step explanation:

1). $14(\frac{1}{2}-t)\leq 28$

$\frac{14}{14}(\frac{1}{2}-t)\leq \frac{28}{14}$

$\frac{1}{2}-t\leq 2$

$-t\leq 2-\frac{1}{2}$

$-t\leq \frac{3}{2}$

t ≥ - $\frac{3}{2}$

2). 15k + 11 ≤ 18k - 5

15k - 18k ≤ -5 - 11

-3k ≤ - 16

3k ≥ 16

k ≥ $\frac{16}{3}$

3). 44y > 11 + 88y - 22y

44y > 11 + 66y

44y - 66y > 11

-22y > 11

22y < -11

$\frac{22y}{22}$

y < $-\frac{1}{2}$

4). $\frac{7}{9}(b - 27) > \frac{49}{81}$

$\frac{7}{9}(b - 27)\times \frac{9}{7} > \frac{49}{81}\times \frac{9}{7}$

(b - 27) > $\frac{7}{9}$

b > $\frac{7}{9}+27$

b > $\frac{250}{9}$

5). 11w - 8w ≥ 14w

3w - 14w ≥ 0

-11w ≥ 0

w ≤ 0

7 0

3 years ago

Pls solve the simultaneous equation in the attachment.

siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

$\frac{x}{2}-\frac{y}{5}=1$ ----> equation A

$y-\frac{x}{3}=8$ ----> equation B

Multiply equation A by 10 both sides to remove the fractions

$5x-2y=10$ ----> equation C

isolate the variable y in equation B

$y=\frac{x}{3}+8$ ----> equation D

we have the system of equations

$5x-2y=10$ ----> equation C

$y=\frac{x}{3}+8$ ----> equation D

Solve the system by substitution

substitute equation D in equation C

$5x-2(\frac{x}{3}+8)=10$

solve for x

$5x-\frac{2x}{3}-16=10$

Multiply by 3 both sides

$15x-2x-48=30$

$15x-2x=48+30$

Combine like terms

$13x=78$

$x=6$

<em>Find the value of y</em>

$y=\frac{x}{3}+8$

$y=\frac{6}{3}+8$

$y=10$

The solution is the ordered pair (6,10)

Part b) we have

$xy=21$ ---> equation A

$x+5y=22$ ----> equation B

isolate the variable x in the equation B

$x=22-5y$ ----> equation C

substitute equation C in equation A

$(22-5y)y=21$

solve for y

$22y-5y^2=21$

$5y^2-22y+21=0$

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

$x=22-5(1.4)=15$

For y=3

$x=22-5(3)=7$

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0

4 years ago

If a new data point at 12 is added to the graph, which will be true?

love history [14]

Answer:

the answer is C on edge

7 0

3 years ago

Read 2 more answers