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nalin [4]
4 years ago
5

What is the value of the expression below 476 \17

Mathematics
1 answer:
disa [49]4 years ago
4 0

476 \div 17 = 28
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Alternate exterior angles ​
exis [7]

Answer:

When  \: two  \: lines  \: are \:  crossed \:  by  \: another \:  line \:  (called  \: the \:  Transversal \: ):  \: Alternate \:  Interior  \: Angles \:  are  \: a \:  pair  \: of  \: angles  \: on \:  the \:  inner  \: side  \: of  \: each  \: of \:  those  \\  \\  \\  \\  \\ two \:  lines  \: but  \: on \:  opposite  \: sides  \: of  \: the  \: transversal.

hope it helps if it helps don'tforget to like and mark

8 0
3 years ago
If p=12 and q=24, evaluate the following expression:p+q/4​
Rus_ich [418]

Answer:

18

Step-by-step explanation:

12+24/4

12+6

18

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7 0
3 years ago
(-5,8) and (-10,3) what is the slope
ale4655 [162]

Answer:

The slope is 1.

Step-by-step explanation: when you graph them you do the rise/run you get 1 which is the slope.

4 0
3 years ago
Read 2 more answers
Mary Grace has 3 more Jolly Ranchers than Isabella. If Isabella has 10 Jolly Ranchers, how many do they have total?
PilotLPTM [1.2K]

Answer:23

Step-by-step explanation:

10+3=13 so that means that mary has 13 and isabella has 10

Then if you add 13+10=23

so they have 23 jolly ranchers in all.

5 0
3 years ago
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The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t
zloy xaker [14]

Answer:

103=  p small

plarge = 123

Step-by-step explanation:

We know that the the ratio of the areas is the scale factor squared/

Larger triangle over smaller triangle

72

----- = scale factor ^2

50

simplify by dividing by 2 on top and bottom

36

----- = scale factor ^2

25

Take the square root of each side

sqrt(36)

-------------- = sqrt(scale factor ^2)

sqrt(25)

6

-------------- = scale factor

5

The ratio of the perimeters is the scale factor

p large             6

-------------- = ----------------

 p small                5

Using cross products

6 p large = 5 p small

We know the sum is 226

p large + p small = 226

p large = 226 - p small

We have 2 equation and 2 unknowns

6 p large = 5 p small

Substitute for p large

6 (226 - p small) = 5 p small

1356 - 6 p small = 5 p small

Add 6 p small to each side

1356 = 11 p small

divide by 11

1356/11 =  p small

P large = 226-1356/11

p large = 2486/11-1356/11

plarge = 1130/11

The solution requires whole number answers so

1356/11 =  p small

123.27 which rounds to 123

plarge = 1130/11

plarge = 102.7272 = 103

6 0
3 years ago
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