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3 years ago

What is the value of each equation 17/25-9/25 63/46-81/46

Mathematics

1 answer:

agasfer [191]3 years ago

7 0

8/25

-18/46
(if it says to simplify: -9/23)

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Write a word problem using the equation -4-10

Nata [24]

If you were to borrow $4 from one person and you borrow $10 more from another person. How much do you owe altogether?

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4 years ago

Solve the system of equations: 6x - 5y = 15 x = y + 3

Anettt [7]

Answer:

x = 0, y = -3

Step-by-step explanation:

plug in x as y + 3 into the first equation

6(y+3) - 5y = 15

6y+18 - 5y = 15

y = -3

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3 years ago

Write the quadratic function f(x) = x2 - 5x + 3 in vertex form.

mixer [17]

So the vertex formula is A(X - H)^2 + K so find the vertex and plug all numbers in

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3 years ago

Will someone please ansewer please

docker41 [41]

Answer:

its the second one

Step-by-step explanation:

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3 years ago

In Exercises 1 and 2, find the equilibrium solutions of the differential equation specified.1) dy/dt = (y + 3)/(1 - y)2) dy/dt =

Aleks [24]

Answer:

1. Equilibrium solution: y= -3

2. Equilibrium solution y= ±1.414

Step-by-step explanation:

Thinking process:

The equilibrium solution can only be derived when $\frac{dy}{dt} = 0$

1. Let's look at the first equation:

$\frac{dy}{dt} = \frac{(y+3)}{(1-y)}$

equating $\frac{dy}{dt} = 0$ to the expression $\frac{(y+3)}{(1-y)}$ gives

y + 3 = 0

y = -3

Therefore, the equilibrium solution occurs at y = -3

2. Let's look at the second solution:

$\frac{dy}{dy} = \frac{(t^{2}- 1) (y^{2}-2) }{y^{2}-4 }$

dividing each side by (t²-1) gives

1/(t²-1) $\frac{dy}{dt}$ = (y²-2)/ (y²-4)

factorizing the right hand side gives:

at equilibrium: $\frac{dy}{dt} = 0$ , then

y² - 2 = 0

solving for y gives y = ±√2

= ±1.414

5 0

4 years ago