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4 years ago

What type of information is NOT found on a consumer's credit report?

Mathematics

2 answers:

daser333 [38]4 years ago

6 0

Your answer is C. Hope this help :D

serious [3.7K]4 years ago

4 0

C. That's personal stuff that employers don't have access to everything else anyone could look at if they needed it.

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g In a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained

Marat540 [252]

Answer:

95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

Step-by-step explanation:

We are given that in a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained a flu shot.

Firstly, the Pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of residents 65-years or older who had obtained a flu shot = $\frac{28}{111}$ = 0.25

n = sample of residents 65-years or older = 111

p = population proportion of residents who were getting the flu shot

Here for constructing 95% confidence interval we have used One-sample z test for proportions.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.25-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } }$ , $0.25+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } }$ ]

= [0.169 , 0.331]

Therefore, 95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

7 0

3 years ago

PLEASEEEE HELP MEEEEEEEEEE

umka21 [38]

Answer:
should be A. 5x+2

7 0

3 years ago

Write the following inequality in slope-intercept form. –12x – 2y ≥ –42 y ≥ –6x – 21 y ≤ –6x – 21 y ≤ –6x + 21 y ≥ –6x + 21

xxMikexx [17]

Answer:

y ≤ –6x + 21

Step-by-step explanation:

5 0

3 years ago

At a store, customers are randomly selected to participate in a survey. On Friday, there were 500 customers at the store. Out of

Svetlanka [38]

Divide the number of people selected by the total number of people.

90/500 = .18

This means that 18% of the customers were selected for the survey.

If the probability is the same on Saturday, then we can multiply the expected customers by our .18

700 x .18 = 126

126 should be selected for the survey on Saturday.

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3 years ago

A. A mother dolphin is 150.25 meters below sea level. Her calf is 45 meters below sea level.

soldi70 [24.7K]

Answer:

Idk

Step-by-step explanation:

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3 years ago