Answer: it is D)
Step-by-step explanation:
Equation: 21+n=43.23
Process to find n
21+n=43.23
Subtract 21 from both sides
n=22.23
Answer:

Step-by-step explanation:
<em>Time</em><em> </em>is the dependent variable, so you set your function equal to <em>s</em>. Then, the correlation of the graph has a
<em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>] from the y-intercept of
so we choose this answer choice.
I am joyous to assist you anytime.
A second degree polynomial function has the general form:

, where

.
The leading coefficient is a, so we have a=-1.
5 is a double root means that :
i) f(5)=0,
ii) the discriminant D is 0, where

.
Substituting x=5, we have
f(5)=a(5)^2+b(5)+c,
and since f(5)=0, and a is -1 we have:
0=-25+5b+c
thus c=25-5b.
By ii)

.
Substituting a with -1 and c with 25-5b we have:
Finally we find c: c=25-5b=25-50=-25
Thus the function is

Remark: It is also possible to solve the problem by considering the form

directly.
In general, if a quadratic function has leading coefficient a, and has a root r of multiplicity 2, then its form is