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dimaraw [331]
3 years ago
11

Five friends had lunch together. Their

Mathematics
1 answer:
deff fn [24]3 years ago
3 0

Answer:

B and D are the same, but its less than 50 so X < 50

Step-by-step explanation:

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I’ve been stuck on this for 3 hours and got 4 different answers...
mestny [16]

Answer:

14x-8

Step-by-step explanation:

The sides for the square are equal to 2x-5 because that is the square root of the area.  The length of the rectangle is 3x+6 and the width is 3x-6 because that is what you get when you factor the equation.

Now, you have add them up.

4(2x-5)+2(3x-6)+2(3x+6)\\

To take out the line in the middle of the shape we will subtract 2(3x-6) because we are assuming that this equation is equal to the shorter side.  This makes the equation

4(2x-5)+2(3x-6)\\14x-8

If you are looking for a numerical answer, I can't say I know how to get it.

Hope this helps! <3

6 0
3 years ago
Please Help!! Questions 15-17.<br> Show you work<br> Thank you!!
denis-greek [22]

Answer:

Step-by-step explanation:

5 0
3 years ago
Solve for x.<br> 2-[x+4(6-x)+16]-10=38-8x
Diano4ka-milaya [45]

Exact form is x = 86/11

Mixed number form is x = 7 whole number 9/11

7 0
2 years ago
Misty bought a package of three T-shirts for $18.75. What is the unit price per T-shirt?
exis [7]
$18.75/3 shirts= $6.25 per shirt.
5 0
4 years ago
Hi. Please help me with these questions <br> See image for question.Answer no 6 and 7
Gnom [1K]

Answer:

  • 6. See solution
  • 7. k = 2, k = -6

Step-by-step explanation:

6.

<u>Given equation:</u>

  • 2(x + 2)² + p(x + 1) = 0
  • The sum of the roots is q1 and the product of the roots is q2

Need to show that q1+q2 = 0

<h3>Solution</h3>

<u>Bringing the equation into standard form of ax² + bx + c = 0:</u>

  • 2(x + 2)² + p(x + 1) = 0
  • 2x² + 8x + 8 + px + p = 0
  • 2x² + (p + 8)x + (p + 8) = 0

<u>Sum of the roots: </u>

  • q1 = - b/a = -(p + 8)/2

<u>Product of the roots:</u>

  • q2 = c/a = (p + 8)/2

<u>We see that q1 and q2 are opposite numbers, therefore their sum equals zero:</u>

  • q1 + q2 = -(p + 8)/2 +  (p + 8)/2 = 0

=============================================

7.

<u>Given quadratic equation:</u>

  • x² - (k + 2)x + 4 = 0
  • It has equal roots

Need to find the possible values of k

<h3>Solution</h3>

<u>When the quadratic equation has equal roots, then its discriminant is equal to zero:</u>

  • D = 0
  • √b² - 4ac = 0
  • √(-k -2)² - 4*1*4 = 0
  • √k² + 4k + 4 - 16 = 0
  • √k² + 4k - 12 = 0
  • k² + 4k - 12 = 0
  • k = {-4 ± √4² -4*1*(-12)}/2
  • k = (-4 ± √16 + 48)/2
  • k = (-4±√64)/2
  • k = -2 ± 4
  • k = 2, k = -6
7 0
3 years ago
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