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almond37 [142]
3 years ago
9

HELP PLEASEEEEEEEEEEE

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
8 0

Answer:

? = 4

4 is the answer

Step-by-step explanation:

heart = 21

rainbow = 7

unicorn horn = 9

so, we have

heart + rainbow + rainbow = 35

21 + 7 + 7 = 35

heart + unicorn horn + rainbow = 37

21 + 9 + 7 = 37

rainbow + unicorn horn + unicorn horn =25

7 + 9 + 9 = 25

unicorn horn + unicorn horn + rainbow - heart = ?

9 + 9 + 7 - 21 = 4

adelina 88 [10]3 years ago
3 0

Answer:

Which one is at the bottom? if the one at the bottom is 0 then the answer is 0. If its not then its related to pemdas or something else

Step-by-step explanation:

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Answer:

-3x+5

Step-by-step explanation:

The answer is up ahead

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Awnser question and show your work if you can (i will give brainliest
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Answer:

answer is -1.75

Step-by-step explanation:

y = 12 \\ y =  - 4x + 5 \\  \\  \:  \:  \:  \: 12 =  - 4x + 5 \\  - 5 \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \: - 5 \\  \\ 7 =  - 4x \\  \div  - 4 \:  \:  \:  \: on \: both \: sides \\   \\ - 1.75 = x

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3 years ago
Represent the following expressions as a power of the number a where a≠0 a^2*(a^4)^3÷a^13
ivann1987 [24]

Answer:

  • a

Step-by-step explanation:

  • a^2*(a^4)^3:a^{13}=
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3 years ago
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A right rectangular prism is filled to capacity with 152 cubes, each with 12 -inch long edges. What is the volume of the prism?
telo118 [61]
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When an amount of heat Q (in kcal) is added to a unit mass (kg) of a
lisov135 [29]

Answer:

The change in temperature per minute for the sample, dT/dt is 71.\overline {6} °C/min

Step-by-step explanation:

The given parameters of the question are;

The specific heat capacity for glass, dQ/dT = 0.18 (kcal/°C)

The heat transfer rate for 1 kg of glass at 20.0 °C, dQ/dt = 12.9 kcal/min

Given that both dQ/dT and dQ/dt are known, we have;

\dfrac{dQ}{dT} = 0.18 \, (kcal/ ^{\circ} C)

\dfrac{dQ}{dt} = 12.9 \, (kcal/ min)

Therefore, we get;

\dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = {\dfrac{dQ}{dt} } \times \dfrac{dT}{dQ} = \dfrac{dT}{dt}

\dfrac{dT}{dt} = \dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = \dfrac{12.9 \, kcal / min }{0.18 \, kcal/ ^{\circ} C }   = 71.\overline 6 \, ^{\circ } C/min

For the sample, we have the change in temperature per minute, dT/dt, presented as follows;

\dfrac{dT}{dt}  = 71.\overline 6 \, ^{\circ } C/min

8 0
3 years ago
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