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4 years ago

Will someone please answer the highlighted questions for me ?

Mathematics

1 answer:

PIT_PIT [208]4 years ago

3 0

The area of number four, the hexagon, is 841.78.

Hope this helps!

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A positive real number is 2 less than another. When 4 times the larger is added to the square of the smaller, the result is 49.

Kobotan [32]

Answer:

The numbers are

$-2+3\sqrt{5}$ and $3\sqrt{5}$

Step-by-step explanation:

Let

x -----> the smaller positive real number

y -----> the larger positive real number

we know that

A positive real number is 2 less than another

$x=y-2$

$y=x+2$ ----> equation A

When 4 times the larger is added to the square of the smaller, the result is 49

$4y+x^2=49$ ----> equation B

substitute equation A in equation B

$4(x+2)+x^2=49$

solve for x

$x^2+4x-41=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^2+4x-41=0$

$a=1\\b=4\\c=-41$

substitute in the formula

$x=\frac{-4\pm\sqrt{4^{2}-4(1)(-41)}} {2(1)}$

$x=\frac{-4\pm\sqrt{180}} {2}$

$x=\frac{-4\pm6\sqrt{5}} {2}$

$x=-2\pm3\sqrt{5}$

The positive real number is

$x=-2+3\sqrt{5}$

Find the value of y

$y=x+2$

$y=-2+3\sqrt{5}+2$

$y=3\sqrt{5}$

6 0

4 years ago

The function f (x) = 6x + 13 defines a

Mrrafil [7]

Answer:

15, 21, 27

Step-by-step explanation:

Given the function :

f(x) = 6x + 13 ; which defines a sequence for x > 1

The first three terms of the sequence ;

x > 1 ;

Hence x = 2, 3, 4

The sequence :

f(2) = 6(2) + 3 = 12 + 3 = 15

f(3) = 6(3) + 3 = 18 + 3 = 21

f(4) = 6(4) + 3 = 24 + 3 = 27

4 0

4 years ago