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zysi [14]
3 years ago
7

How do you solve 8.4-6.8=-3.2y+16.4

Mathematics
2 answers:
Monica [59]3 years ago
6 0

Answer:

y=4.625

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

AVprozaik [17]3 years ago
4 0

Answer:

  y = 4.625

Step-by-step explanation:

Subtract 16.4 from both sides and collect terms.

  8.4 -6.8 -16.4 = -3.2y +16.4 -16.4

  -14.8 = -3.2y

Divide both sides by -3.2.

  -14.8/-3.2 = (-3.2y)/-3.2

  4.625 = y

The solution is y = 4.625.

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A fair coin is tossed repeatedly with results Y0, Y1, Y2, . . . that are 0 or 1 with probability 1/2 each. For n ≥ 1 let Xn = Yn
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Answer:

False. See te explanation an counter example below.

Step-by-step explanation:

For this case we need to find:

P(X_{n+1} = | X_n =i, X_{n-1}=i') =P(X_{n+1}=j |X_n =i) for all i,i',j and for X_n in the Markov Chain assumed. If we proof this then we have a Markov Chain

For example if we assume that j=2, i=1, i'=0 then we have this:

P(X_{n+1} = | X_n =i, X_{n-1}=i') =\frac{1}{2}

Because we can only have j=2, i=1, i'=0 if we have this:

Y_{n+1}=1 , Y_n= 1, Y_{n-1}=0, Y_{n-2}=0, from definition given X_n = Y_n + Y_{n-1}

With i=1, i'=0 we have that Y_n =1 , Y_{n-1}=0, Y_{n-2}=0

So based on these conditions Y_{n+1} would be 1 with probability 1/2 from the definition.

If we find a counter example when the probability is not satisfied we can proof that we don't have a Markov Chain.

Let's assume that j=2, i=1, i'=2 for this case in order to satisfy the definition then Y_n =0, Y_{n-1}=1, Y_{n-2}=1

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Answer:

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Anya could find out her volume by multiplying 1.5*1.5*4 and then subracting that from 11*8.5.

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Answer:

Seems like someone answered them, because the red writing is right, but here's the answers with explanation

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  • The vertex is the point at which the graph changes direction as we go from left to right.
  • Maximum means the graph is changing direction and going down, so the f(x)-values start becoming smaller. So the graph reached its maximum/highest point and dropped.
  • Minimum means the graph is changing direction and going up, so the f(x)-values start becoming bigger. So the graph reached its minimum/lowest point and started rising
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  2. vertex is (3,44), when you look at f(x) it goes 143, then 88, then 55, then 44, then it changes and starts getting bigger so <em>minimum</em>
  3. vertex is (-4,-5) but this one is different from the first two. f(x) starts with -17 then -9, then -5, then it sort of stops and stays there, then -5 then drops and gets smaller. So it changes at x=-4 so use this point, immediately before the change and it is <em>maximum</em>
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  5. vertex is (1.5,6) the point immediately before the change, and we see f(x) was getting smaller going down, but it changes and goes up and gets bigger so it is <em>minimum</em>
  6. vertex is (0.5,5) because it was getting big then changed and started getting smaller so <em>maximum</em>
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