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topjm [15]
3 years ago
15

Given isosceles ABC, median BD to base AC. Prove ADB=CDB. AB=, AD=, BD=, ADB=

Mathematics
1 answer:
lesya692 [45]3 years ago
5 0

Answer:

1. AB=CB                     def  of isosceles triangle

2. AD=CD DEF           of median

3. BD=DB                    reflexive property

4. ADB=CDB               SSS

Step-by-step explanation:

ummmm its just the right answer trust

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mash [69]
The correct answer is that there is more variability in the heights of the volleyball team members.

The mean absolute deviation shows us how spread out the data is, so the larger the mean absolute deviation the higher the variability.

Both teams have players that are 76 inches tall, so the last two statements cannot be true.
6 0
3 years ago
The joint probability mass function of XX and YY is given by p(1,1)=0p(2,1)=0.1p(3,1)=0.05p(1,2)=0.05p(2,2)=0.3p(3,2)=0.1p(1,3)=
inessss [21]

Answer:

P(Y=1|X=3)=0.125

Step-by-step explanation:

Given :

p(1,1)=0  

p(2,1)=0.1

p(3,1)=0.05

p(1,2)=0.05

p(2,2)=0.3

p(3,2)=0.1

p(1,3)=0.05

p(2,3)=0.1

p(3,3)=0.25

Now we are supposed to find the conditional mass function of Y given X=3 :  P(Y=1|X=3)

P(X=3) = P(X=3,Y=1)+P(X=3,Y=2) +P(X=3,Y=3)

P(X=3)=p(3,1) +p(3,2) +p(3,3)

P(X=3)=0.05+0.1+0.25=0.4

P(Y=1|X=3)=\frac{P(X=3,Y=1)}{P(X=3)} =\frac{p(3,1)}{P(X=3)}=\frac{0.05}{0.4}= 0.125

Hence P(Y=1|X=3)=0.125

8 0
3 years ago
Please help me on this one question! (10th grade level)
Semmy [17]
Make an inequality representing both constraints.
0.5x+y<20
x+y≥24
for a
3 0
3 years ago
Read 2 more answers
Please help, I’ll mark your answer as brainliest.
timama [110]

Already answered here: brainly.com/question/26919792

5 0
3 years ago
1. tan a = cot(a + 10°)
Temka [501]

Answer:

a=40+90n

Step-by-step explanation:

Use a cofunction identity on the right hand side or left hand side...

So \tan(a)=\cot(90-a).

We have the equation:

\tan(a)=\cot(a+10)

Make the above replacement:

\cot(90-a)=\cot(a+10)

Since cotangent has period 180 degrees, we can also write this as:

\cot(90-a+180n)=\cot(a+10)

So solving the following will give us a set of solutions for a:

90-a+180n=a+10

Add a on both sides:

90+180n=2a+10

Subtract 10 on both sides:

80+180n=2a

Divide both sides by 2:

40+90n=a

Symmetric property:

a=40+90n

7 0
3 years ago
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