Answer:
0.999987
Step-by-step explanation:
Given that
The user is a legitimate one = E₁
The user is a fraudulent one = E₂
The same user originates calls from two metropolitan areas = A
Use Bay's Theorem to solve the problem
P(E₁) = 0.0131% = 0.000131
P(E₂) = 1 - P(E₁) = 0.999869
P(A/E₁) = 3% = 0.03
P(A/E₂) = 30% = 0.3
Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :
= 0.999986898 ≈ 0.999987
Answer:
The game is not fair
Step-by-step explanation:
Let us find the sample space. It is the sum of the two spins
1+1 1+2 1+3 1+4
2+1 2+2 2+3 2+4
3+1 3+2 3+3 3+4
4+1 4+2 4+3 4+4
Adding
2,3,4,5
3,4,5,6
4,5,6,7
5,6,7,8
P(2) = 1/16
p(3) = 2/16
p(4) = 3/16
p(5) = 4/16
p(6) = 3/16
p(7) = 2/16
p(8) = 1/16
Player A gets a point if the sum is 6 or more
P (6,7,8) = P (6) + P(7) + P(8) since they are independent event
=( 3+2+1) /16 = 6/16 = 3/8
Player P gets a point if the sum is less than 6
P (2,3,4,5) =P (2) + P(3) + P(4 + P(5)
(1+2+3+4)/16 = 10/16= 5/8
Player B has a better chance of winning, so the game is not fair
Answer:
39.3%
Step-by-step explanation:
Answer:
Step-by-step explanation:
Get x to one side
So minus 90 from each side
-90÷-3=30
Answer: x=30
