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Trava [24]
2 years ago
14

Hey guys I need your help on this!!

Mathematics
1 answer:
kogti [31]2 years ago
7 0

Answer:

Domain: (-∞, ∞) or All Real Numbers

Range: (0, ∞)

Asymptote: y = 0

As x ⇒ -∞, f(x) ⇒ 0

As x ⇒ ∞, f(x) ⇒ ∞

Step-by-step explanation:

The domain is talking about the x values, so where is x defined on this graph? That would be from -∞ to ∞, since the graph goes infinitely in both directions.

The range is from 0 to ∞. This where all values of y are defined.

An asymptote is where the graph cannot cross a certain point/invisible line. A y = 0, this is the case because it is infinitely approaching zero, without actually crossing. At first, I thought that x = 2 would also be an asymptote, but it is not, since it is at more of an angle, and if you graphed it further, you could see that it passes through 2.

The last two questions are somewhat easy. It is basically combining the domain and range. However, I like to label the graph the picture attached to help even more.

As x ⇒ -∞, f(x) ⇒ 0

As x ⇒ ∞, f(x) ⇒ ∞

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Read 2 more answers
The perimeter of a rectangle is 150 cm. the length is 4 cm greater than the width find the width and length
Fudgin [204]

Let's call the width of our rectangle w and the length l. We can say l = w + 4, since the length is equal to 4 cm greater than the width.


Also remember that the perimeter of a rectangle is the sum of two times the width and two times the length, or P = 2l + 2w. To solve this problem, we can substitute in the information we know, as shown below:

150 = 2(w + 4) + 2w

150 = 4w + 8

142 = 4w

w = \frac{71}{2}


Now, we can substitute in the width we found into the formula for length, which is l = w + 4:

l = \frac{71}{2} + 4

l = \frac{79}{2}


The width of our rectangle is \boxed{\frac{71}{2} \,\, \textrm{cm}} cm and the length of our rectangle is \boxed{\frac{79}{2} \,\, \textrm{cm}}

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