Answer:

Step-by-step explanation:
Given
ID Card of 5 digits
Possibly Digits = {0,1...,9}
Required
Probability that a card has exact number 94213
First, we have o determine the total possible number of ID card numbers
Let the card number be represented by ABCDE
Given that repetition of digits is not allowed;
<em>A can be any of 10 digits</em>
<em>B can any of the remaining 9 digits</em>
<em>C can be any of the remaining 8 digits</em>
<em>D can be any of the remaining 7 digits</em>
<em>E can be any of the remaining 6 digits</em>
<em />
Total number of cards = 10 * 9 *8 * 7 * 6
Total = 30240
Provided that the card number is generated at random; each card number has the same probability of 
Hence, the probability of having 94213 is 
Given, (9x - 4)(9x + 4) = ax² - b
From algebraic identities:
We know, (a + b)(a - b) = a² - b²
Now, 81x² + 36x - 36x - 16 = ax² - b
81x² - 16 = axis² - b
So ax² = 81x²
a = 81
-b = -16
b = 16
Solution
Therefore, the value of a is 81.
<h2>MyHeritage</h2>
Answer:
f(1)=4
Step-by-step explanation:
f(1)=3(1)^4-(1)^2+4(1)-2
f(1)=3(1)-1+4-2
f(1)=3-1+4-2
f(1)=4