The perimeter = sum of all sides
= 120 + 80 + 50
= 250
So 250 - 3
247
Left space for gate
Now cost of fencing = Rs 20/per meter
= 247 × 20
= Rs 4,940
Now the area of the triangular park can be found using heron's formula
S = (a+b+c)/2
S = (120+80+50)/2
S = 250/2
S = 125
Now
Herons formula = √s(s-a)(s-b)(s-c)
√125(125-120)(125-80)(120-50)
√125(5)(45)(70)
√5×5×5×5×5×3×3×5×14
After Making pairs
5×5×5×3√14
375√14
Therefore 375√14m is the area of the triangular park
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(x+2) + 3(x+2)
x+2+3x+6
.. ( collect like terms )
= 4x+2+6
= 4x + 8 is your answer
The equation of the line which passes through the point (-5, 3) and is parallel to the equation 3x -5y = 30 is; 3x -5y = 30.
<h3>What is the equation of the line?</h3>
Since the line is parallel to the given line; 3x -5y = 30 whose slope is; 3/5.
Hence, since the two lines have equal slopes;
3/5 = (y-3)/(x-(-5))
3/5 = (y-3)/(x+5)
5y -15 = 3x +15
3x -5y = 30
Read more on equation of a line;
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8X + 8 > 7x + 14
subtract 7x and 8 from both sides
x > 6
A whole number? ok. 24x10^4. usually though you would use standard form so it would be 2.4x10^5
