Let the capacity of bus be x students
And van be y students, now ;
From the given statements we get two equations ~
multiply the equation (2) with 2 [ it won't change the values ]
Now, deduct equation (1) from equation (3)
Therefore each bus can carry (x) = 45 students
Now, plug the value of x in equation (1) to find y ~
Hence, each van can carry (y) = 17 students in total.
Answer:
-3/5
Step-by-step explanation:
tan = opp/adj using pathagorean the hypt is 5
cos = 3/5
tan is negative in quad 2 and 4
sin is positive in quad 1 and 2
so because tan is negative and sine is positive the cosine is negative
-3/5
ok, we need to factor the expression
since the expression divisible by y-2, then
since 6=2k, then k=c=3
Answer:
a(n) = 37 - 5(n -1)
Step-by-step explanation:
Notice that each new term is obtained by subtracting 5 from the previous term. Thus, this is an arithmetic sequence with common difference -5 and first term 37.
The explicit formula for the nth term is a(n) = a(1) - 5(n - 1) = 37 - 5(n -1)
Answer:
2 to 1; 2:1
Step-by-step explanation:
There are two cups of water and one cup of rice. It's a two to one ratio.
