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3 years ago

6

If the line passing through the points (a, 1) and (−17, 8) is parallel to the line passing through the points (0, 5) and (a + 2,

1), what is the value of a?

1 answer:

stellarik [79]3 years ago

4 0

Parallel line means the same slope
（8-1）/(-17-a)=(1-5)/(a+2)
so a is 18

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Help Me With This Please I'll Give Branliest to Who Can answer simple

ahrayia [7]

28. This equation satisfies the condition
-x - 10 = -17

29. You can use this equation
x/5 + 5 = 0

30. The error is dividing the equation first by 3. The solution should have been
3x + 2 = 15
3x = 15 - 2
3x = 12
3x/3 = 12/3
x = 4

31.
x/4 - 6 = 2
x/4 = 2 + 6
x/4 = 8
x = 8(4)
x = 32

5 0

4 years ago

Expand 5a(3a-2b). Thank you!

Thepotemich [5.8K]

Answer:

15 a^2 + -10 a b

Step-by-step explanation:

Expand the following:

5 a (-2 b + 3 a)

Hint: | Distribute 5 a over -2 b + 3 a.

5 a (-2 b + 3 a) = 5 a (-2 b) + 5 a (3 a):

-2 5 a b + 5 3 a a

Hint: | Combine products of like terms.

5 a×3 a = 5 a^2×3:

5×3 a^2 - 2×5 a b

Hint: | Multiply 5 and 3 together.

5×3 = 15:

15 a^2 - 2×5 a b

Hint: | Multiply 5 and -2 together.

5 (-2) = -10:

Answer: 15 a^2 + -10 a b

6 0

4 years ago

Read 2 more answers

Can you find the slope-intercept equation between each pair of coordinate points and type the correct code? Please remember to t

Annette [7]

Answer:

Step-by-step explanation:

4 0

3 years ago

When the coffee is brewed according to directions, a pound of coffee beans yields 50 cups of coffee (4 cups = 1 qt). How many kg

Basile [38]

we know that

$1\ pound=0.453592\ kg$

in this problem

a pound of coffee beans yields $50$ cups of coffee

so

by proportion

Find the kg of coffee that are required to produce $100$ cups of coffee

$\frac{0.453592}{50}\frac{kg}{cups} =\frac{x}{100}\frac{kg}{cups}\\ \\50*x=100*.453592\\ \\x =0.453592*100/50\\ \\x=0.907184\ kg$

therefore

<u>the answer is</u>

$0.907184\ kg$

5 0

4 years ago

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Which of the following can be added without altering any of the fractions?

S_A_V [24]

Answer:

a

Step-by-step explanation:

$\frac{3x}{x-1}$ + $\frac{8}{x-1}$

These fractions have a common denominator and so do not require to be altered.

The numerators can be added to simplify, that is

= $\frac{3x+8}{x-1}$

The remaining fractions have different denominators and would require to be altered before they could be added.

4 0

3 years ago