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miss Akunina [59]
3 years ago
15

Find the area? Helppp helppppp

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
5 0

Answer:

20.25

Step-by-step explanation:

You multiply 7.5 by 5.4 and divide by 2. Base times height divided by 2. It works for triangles. 7.5x5.4=40.5 ... 40.5/2= 20.25

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if you could generate energy by fusing the hydrogen in solution a, how much of the solution would you need to generate the elect
iogann1982 [59]

Answer:

We know that:

Energy released by fusion of hydrogen in 1 liter of solution A = 7.6x10^10 J

Energy used daily in a certain family home = 3x10^4 J

(you did not write the units, so i suppose that are the same in both cases)

Then, if x is the number of liters of solution A used, the energy produced will be:

E(x) = x*7.6x10^10 J

And we want this equal to 3x10^4

then:

E(x) = x*7.6x10^10 J = 3x10^4 j

now we solve this for x.

x = (3x10^4 j)/(7.6x10^10 j) = 3.9x10^-7

Then you need to use 3.9x10^-7 L of solution a.

4 0
4 years ago
In a recent survey, 64 % of the community favored building a police substation in their neighborhood. If 14 citizens are chosen,
kozerog [31]

Answer: 0.1840

Step-by-step explanation:

The binomial probability formula :-

P(X)=^nC_x\ p^x(1-p)^{n-x}, here n is the number total of trials , p is the probability of getting success in each trial and P(x) is the probability of getting success in x trial.

Given : The probability of the community favored building a police substation in their neighborhood = 0.64

If 14 citizens are chosen, then the probability that exactly 8 of them favor the building of the police substation will be :-

P(8)={14}^C_{8}\ (0.64)^{8}(1-0.64)^{14-8}\\\\=\dfrac{14!}{8!6!}\times(0.64)^8(0.36)^{6}\\\\0.183996740126\approx0.1840

Hence, the probability that exactly 8 of them favor the building of the police substation = 0.1840

5 0
4 years ago
Two angles are supplementary. If Angle M is 2x² and Angle P is 130°, then find the value of x and the measure of each missing an
xenn [34]

Answer:

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8 0
3 years ago
The number of people in a car that crosses a certain bridge is represented by the random variable X, which has a mean value μX =
Alona [7]

Let Y be the total amount of money paid by any given set of passengers. If there are X passengers in a car, then the driver must pay a toll of Y=0.5X+3.

Then Y has first moment (equal to the mean)

E[Y]=E[0.5X+3]=0.5E[X]+3E[1]=0.5\mu_X+3=\boxed{4.35}

and second moment

E[Y^2]=E[0.25X^2+3X+9]=0.25E[X^2]+3E[X]+9E[1]=0.25E[X^2]+3\mu_X+9

Recall that the variance is the difference between the first two moments:

\mathrm{Var}[X]=E[X^2]-E[X]^2\implies E[X^2]={\sigma^2}_X+{\mu_X}^2

\implies E[Y^2]=0.25({\sigma^2}_X+{\mu_X}^2)+3\mu_X+9\approx19.22

\implies\mathrm{Var}[Y]=E[Y^2]-E[Y]^2=\boxed{0.3}

3 0
4 years ago
How many smaller rectangles are there in an area model that represents 27 times 83 Why? What are their dimensions?
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6 0
3 years ago
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